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1 vote
1 answer
57 views

What happens to the fermion spin when I move around it in a full circle

I would like to understand the actual meaning of the description of a fermion as a spinor. I have a background in QFT and understand the calculations, but there is a leap to the actual experiment ...
ziv's user avatar
  • 1,734
0 votes
1 answer
73 views

$2\pi$-rotation of fermionic states vs. fermionic operators

Given a fermionic state $|\Psi\rangle$, a $2\pi$ rotation should transform it as \begin{equation} |\Psi\rangle \quad\to\quad -|\Psi\rangle \,, \end{equation} On the other hand, given a fermionic ...
Mateo's user avatar
  • 426
3 votes
0 answers
50 views

Field strength renormalization for fermions

Following section 7.1 and 7.2 in Peskin and Schroeder (P&S), I've tried to consider what the derivation of the LSZ formula looks like for (spin $1/2$) fermions (in the text, they explicitly ...
User3141's user avatar
  • 863
0 votes
0 answers
31 views

How to derive Fermion Propagator for Special Kinetic Term?

I am currently working through chapter 75 of the book on QFT by Srednicki. There, he considers the example of a single left-handed Weyl field $\psi$ in a $U(1)$ gauge theory. The Lagrangian, written ...
Niels Slotboom's user avatar
2 votes
1 answer
74 views

Product of spinors in Dirac field anticommutators

I am reading a "A modern introduction to quantum field theory" by Maggiore and on page 88 it shows the anticommutators of the Dirac field: $$ \{\psi_a(\vec{x},t),\psi_{b}^{\dagger}(\vec{y},t)...
Andrea's user avatar
  • 613
3 votes
1 answer
155 views

Mean field and interacting Dirac QFT: channels and spinors

I am dealing with a QFT of Dirac fermions with an interaction term $$L_I=\bar\psi\psi\bar\psi\psi=\psi^\dagger\gamma^0\psi\psi^\dagger\gamma^0\psi,$$ with $\gamma^0$ a Dirac matrix and $\psi$, $\psi^\...
TopoLynch's user avatar
  • 503
1 vote
2 answers
188 views

Massless QED modified Lagrangian

Consider a massless theory of QED, with Lagrangian $$\mathcal{L}_{QED}= -\frac{1}{4}F_{\mu\nu}F^{\mu\nu}+\bar{\Psi}i\gamma^{\mu}\partial_{\mu}\Psi+ e\bar{\Psi}\gamma^{\mu}A_{\mu}\Psi$$ Is there any ...
schris38's user avatar
  • 3,992
1 vote
1 answer
108 views

When does the spinor need to be in a Grassmann variable?

Follow the closed question When does the spinor need to be in a grassmann variable? -- Does the spinor in the spinor representation of the space-time symmetry Lorentz space-time symmetry, like $so(1,...
Марина Marina S's user avatar
3 votes
2 answers
239 views

Connection between column matrix and Grassmann numbers in Dirac field

In canonical quantization the Dirac equation is a complex column matrix, while in path integral formulation it's Grassmann numbers. Is there a formula to convert from complex matrix to Grassmann ...
JavaGamesJAR's user avatar
2 votes
1 answer
138 views

Spinor index, dirac field equation

Sometimes I read anticommute $$\{\psi(x),\psi^\dagger(y)\}=\delta^{(3)}(x-y)$$ Sometimes, $$\{\psi_a(x),\psi_b^\dagger(y)\}=\delta^{(3)}(x-y)\delta_{ab}$$ Are they the same, second one just emphasis ...
Li Chiyan's user avatar
  • 326
0 votes
0 answers
88 views

Scattering right handed fermions

Assume we have a QED like vector exchange, and I scatter only right handed electron-positron pair- ${e}_ R^+ e_R^-\to e_R^+ e_R^-$. Am I correct that There is no s-channel amplitude-they cannot ...
GRrocks's user avatar
  • 2,758
4 votes
0 answers
102 views

Are there non-lagrangian field theories for massive Weyl spinors?

It is a well-known fact that a chiral fermion is massless, since the mass term involves both a right-handed and a left-handed field. If you have one chirality only there are no mass terms one can ...
AccidentalFourierTransform's user avatar
-2 votes
2 answers
874 views

Fermion Determinant [closed]

When we calculate fermion determinant for either Majorana or Weyl spinors, why do we get an extra factor of half in the coefficient of the determinant as compared to the Ghost determinant?
Saurabh Pant's user avatar
5 votes
1 answer
114 views

Internal flavor symmetry of the $N$ left-handed complex Weyl spinors v.s. $N$ real Majorana spinors: ${\rm U}(N)$ vs. ${\rm O}(2N)$ or ${\rm O}(N)$

Consider 4d spacetime, it seems that for massless particles, we can easily change the left-handed complex Weyl spinor basis (2 component in complex $\mathbb{C}$ for Euclidean spacetime Spin(4)) to ...
ann marie cœur's user avatar
2 votes
2 answers
543 views

Can we derive free field expansion formula for the spin-1/2 Dirac field?

The Dirac field has the expansion $$\Psi(x)=\int\frac{d^3p}{\sqrt{(2\pi)^32E_p}}\sum\limits_{s=1,2}\Big(b_s(p)u^s(p)e^{-ip\cdot x}+d^\dagger_s(p)v^s(p)e^{+ip\cdot x}\Big)$$ where $b_s$ and $d_s$ are ...
Solidification's user avatar

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