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Questions tagged [quantum-chromodynamics]

Quantum-ChromoDynamics (QCD) is the quantum field theory believed to describe the strong nuclear force.

0 votes
1 answer
94 views

Sum rules for parton distribution functions

In Schwarz, the parton distribution functions for proton has the following sum rules, $$ \int dx f_u(x)=2\quad,\quad\int dxf_d(x)=1 $$ where $x$ is the fraction of momenta of proton carried by the ...
1 vote
0 answers
35 views

Evidence of more generations in the QCD beta function

We know that the beta function for QCD is $$ \beta = -\left(11 - \dfrac{2N_f}{3}\right), $$ where $N_f$ is the number of fermions in the theory. We have $\beta_{\text{SM}} = -7$. Now, my question is, ...
0 votes
1 answer
47 views

Is color charge internal symmetry or global symmetry?

I was told the color charge in the standard model could not be observed directly. This sounded like the gauge field $\vec A$ in the electromagnetism. However, it is a discrete charge and does have ...
5 votes
1 answer
543 views

Is quark and gluon orbital angular momentum predicted to have the rest of the proton's spin?

The Phys.org news item How did the proton get its spin? outlines various experiments that probe proton structure and are sensitive to spin, and the current news is that CEBAF's major energy upgrade ...
3 votes
1 answer
66 views

How is the mass distributed in ordinary matter?

How is the mass distributed in ordinary matter? In the ordinary things around us, we know that most of the mass is in the cores of the atoms, the electrons around it contributing only a very small ...
0 votes
1 answer
59 views

Visualization of a gauge field with non-null winding number

In QCD you may add the term $\mathcal{L}_{\theta} = \theta\dfrac{g^2}{16\pi^2} \text{Tr}F\tilde{F}$, which turns out to be a total derivative. Now, it can be proven that the action of this lagrangian ...
1 vote
0 answers
60 views

Spinor-helicity formalism: relationship between 1 and 2 reference vector setups

The spinor-helicity formalism is usually set up so that for a massless vector boson (photon or gluon) with momentum $k$ an arbitrary reference momentum $p$ is introduced and the corresponding ...
1 vote
1 answer
286 views

$u$-channel in $gg \rightarrow u\bar{u}$

I've seen that for the QCD process $gg \rightarrow u\bar{u}$, where $g$ is a gluon and $u, \bar{u}$ are the up quark and the corresponding antiquark, there is $s$, $t$ and $u$ channels. I perfectly ...
1 vote
1 answer
298 views

Proton-proton collisions cross section plot by Stirling

I am struggling to understand some details of the cross section plot by Stirling that is very often shown when talking about LHC physics. See e.g. here: http://www.hep.ph.ic.ac.uk/~wstirlin/plots/...
0 votes
1 answer
81 views

$SU(3)$ color charge

Is the color charge the Noether charge due to the "global" $SU(3)$ symmetry of the QCD Lagrangian, or is it due to the "local" symmetry of the QCD Lagrangian?
3 votes
2 answers
130 views

Can an electron be produced inside a proton?

We know that inside a proton there is a sea of quarks, antiquarks and gluons. This happens as the valence quarks emit gluons which then split into a quark-antiquark pairs. These pairs become gluons ...
6 votes
1 answer
273 views

Photon-Gluon annihilation in QCD

I am starting to learn about QCD, and I wanted to calculate the squared matrix elements for photon-gluon annihilation into a quark and an anti-quark. However, I am having trouble writing down the ...
-2 votes
1 answer
68 views

What makes electric and magnetic fields in Yang-Mills theories gauge co-variant?

Specifically in QCD, why is it so?
8 votes
1 answer
2k views

Peccei-Quinn-symmetry and effective Lagrangian for the Axion field

To solve the strong CP-problem Peccei and Quinn suggested the use of a new $U(1)$-symmetry called the PQ-symmetry. For this symmetry they constructed an effective Lagrangian involving the Nambu-...
0 votes
0 answers
39 views

Wilson loop is not an element of $\mathrm{SU}(3)$ in color deconfinement

The center symmetry in QCD comes from the $$a\ \mathcal{P}\mathrm{exp}\left(ig_s \int_C dx^\mu \ A_\mu(x)\right) a^{-1} = \mathcal{P}\mathrm{exp}\left(ig_s \int_C dx^\mu \ A_\mu(x)\right),$$ where $C$ ...

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