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1 vote
1 answer
83 views

Asymptotic Freedom QCD

I'm trying to understand the derivation of asymptotic freedom with the renormalisation group equations. I'm reading Taizo Muta's book on QCD. What I don't understand is how he obtains the last ...
Gogoman96 X's user avatar
0 votes
1 answer
81 views

Possible cases of matter fields for $SU(2)$ theory which retains asymptotic freedom?

Let us assume $4$ spacetime dimensions. QCD, the $SU(3)$ gauge theory with quarks as the matter fields, have the asymptotic freedom property as long as there are 16 quark flavors of mass below the ...
Keith's user avatar
  • 1,669
0 votes
0 answers
244 views

One-loop renormalization of the gauge coupling

Quoting Yuji Tachikawa, chapter 3 of "${\cal N}=2$ Supersymmetric Dynamics for Pedestrians": Recall the one-loop renormalization of the gauge coupling in a general Lagrangian field theory $$...
user avatar
3 votes
1 answer
258 views

What makes the (non-abelian) strong interaction so special that it leads to confinement?

The strong interaction has a coupling constant of $\alpha_s(91GeV)\approx 0.1$ whereas the weak interaction has a much lower coupling constant $\alpha_w \approx 10^{-6}$. Both theories are non-abelian ...
Frederic Thomas's user avatar
3 votes
0 answers
124 views

The 1-loop anomalous dimension of massless quark field for $SU(N)$ gauge theory with $n_f$ quark flavours

Considering $SU(N)$ gauge theory with $n_f$ massless quarks I want to find the anomalous dimension to order of 1-loop of the massless quark field, that defined by: $$\gamma_q(g^{(R)})=\frac{1}{2Z_q}\...
Daniel Vainshtein's user avatar
5 votes
1 answer
375 views

How can we tell a theory is confining?

Physically, I understand what it means for a theory to be confining. The elementary particles are not observable, but only composite particles are. The classic example is QCD, where quarks are ...
fewfew4's user avatar
  • 3,514
0 votes
0 answers
288 views

Intuition for Asymptotic Freedom

In QED, the $\beta$-function has a positive sign. This means that the coupling increases at higher energies, or equivalently, smaller length scales. This picture is made intuitively clear by the ...
user avatar
5 votes
2 answers
530 views

What is relevant for Yang-Mills theory below $d = 4$?

There are two ways to write the Lagrangian for Yang-Mills, differing by the scaling of the Yang-Mills field. Fancy theorists tend to write $$S = \int d^dx \, \frac{1}{4e^2} \, \text{tr}(F^2)$$ while ...
knzhou's user avatar
  • 103k
7 votes
1 answer
442 views

Is Yang-Mills theory confining in any dimensions?

What is the current understanding of Yang-Mills theory (pure non-Abelian gauge theory without matter field) in the infrared limit? (To avoid the subtlety of renormalizability, we may restrict our ...
Everett You's user avatar
  • 11.9k
5 votes
1 answer
262 views

Would the existence of more than 16 quark flavors make QCD deconfinning?

Consider the QCD beta function. Its expansion in powers of the coupling is $$\beta(\mu)=-(\beta_0a(\mu)+\beta_1a^2(\mu)+\ldots)$$ where $a=\alpha/4\pi$. For simplicity let's neglect everything but ...
Yossarian's user avatar
  • 6,067
4 votes
0 answers
322 views

Why is QCD hard to solve if I know the beta functions?

Why is it still hard to solve QCD if we know the beta functions of the coupling? Aren't only the loops causing problems? And am I not able to write every possible interaction exact at tree-level with ...
dan-ros's user avatar
  • 2,147
16 votes
1 answer
2k views

Are "confinement" and "asymptotic freedom" two sides of the same coin?

On Wikipedia it says that the two peculiar properties of quantum chromodynamics (QCD) are: confinement and asymptotic freedom. Asymptotic freedom is the idea that at low energies we cannot use ...
Hunter's user avatar
  • 5,228