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0 votes
0 answers
83 views

How does the electroweak interaction and QCD form $SU(2)$ and $SU(3)$?

I'm trying to get a foothold into quantum field theory from a mathematical background. I see the use of $SU(2)$ and $SU(3)$ in gauge theory and wonder the following questions to help me bring QFT ...
Andreas Tzionis's user avatar
3 votes
2 answers
313 views

Normalisation of QCD Lagrangian

In QCD, and more generally in representations of $\mathfrak{su}(N)$, there is a freedom to choose the normalisation of the generators, $$ \mathrm{Tr} \, \left[R(T^a) R(T^b)\right] = T_R \delta^{ab}.\...
JCW's user avatar
  • 264
2 votes
0 answers
68 views

Abelian theories with more than one charge

I have a question about the non-abelian character of QCD. In order to write a gauge-invariant Lagrangian, there must be a term with the strength tensor $X^{\mu\nu}_{a}X_{\mu\nu}^{a}$ where $$ X^a_{\mu\...
Renan Nobuyuki Hirayama's user avatar
1 vote
2 answers
746 views

How does the underlying symmetry of QCD imply the allowance of a 4-gluon vertex?

Quantum chromodynamics allows for a four-gluon vertex such as this, in a diagram Such a vertex would never be allowed in quantum electrodynamics, which has an underlying U(1) gauge symmetry. I know ...
Featherball's user avatar
2 votes
1 answer
529 views

$U(N)$ & $SU(N)$ : What's the conceptual difference in Gauge Theory?

I know the mathematical difference that one means $ absolutevalue(det) = 1$ and one means det = 1 (rotation) and that ones the subgroup of the other and so on. But: has a local/gauged $SU(3)$ ...
VN23's user avatar
  • 91
4 votes
1 answer
2k views

Why quarks in the fundamental and gluons in the adjoint?

I have been told that in gauge theories “fermionic matter goes in the fundamental rep of $SU(N)$, while gauge fields go in the adjoint rep”. I understand how this works, and for instance, in QCD,...
MBolin's user avatar
  • 1,154
4 votes
1 answer
159 views

QCD from chirally segregated, gauged $SU(3)_L \times SU(3)_R$?

There are already theory papers out there in which color $SU(3)_C$ is actually the diagonal subgroup of multiple $SU(3)$ factors. But due to a comment by @zooby, a new twist on this idea occurred to ...
Mitchell Porter's user avatar
1 vote
0 answers
137 views

Why is $SU(3)$ and not $U(3)$ the correct gauge symmetry? [duplicate]

If quarks come in three colours $r$, $g$ and $b$ than (neglecting all other quantum numbers and spacial freedom for now) a state of a quark would be a vector in $\mathbb{C}^3$. If we are now looking ...
Daan's user avatar
  • 123
1 vote
0 answers
50 views

The remained global flavor symmetries of massless quarks after gauging electromagnetic $U(1)$

For $N_f$ numebr of massless quarks, we know that there are global symmetries $$ \frac{SU(N_f)_L \times SU(N_f)_R \times U(1)_V}{Z_{N_f}} $$ here $U(1)_V$ is the same as $U(1)$-Baryon number ...
ann marie cœur's user avatar
12 votes
2 answers
2k views

$SU(3)$ vs $SO(3)$ color gauge

I have kind of a dumb question: what would happen if the color gauge group is $SO(3)$ instead of $SU(3)$, assuming there are still colors and physical states are still color singlets? Will we e.g. get ...
To Chin Yu's user avatar
11 votes
0 answers
445 views

Is the QCD Lagrangian without a $\theta$-term invariant under large gauge transformations?

In his book "Quantum field theory", Kerson Huang states that we need to add the term $$\frac{i\theta}{32\pi^2}G_{\mu\nu}^a \tilde{G}_{\mu\nu}^a$$ to the Lagrangian, to make it invariant under large ...
jak's user avatar
  • 10.1k
3 votes
1 answer
270 views

How many glueballs are there?

As I understand there are eight types of gluons (linear combinations of color/anticolor pairs with varying amplitudes) which can combine (for very short periods) to form glueballs. If there were no ...
Charles's user avatar
  • 756