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2 votes
1 answer
43 views

Why does (oxidized) aluminum have a diffuse optical appearance?

Unoxidized aluminum has a shiny appearance like typical metals. However in air aluminum rapidly oxidizes, giving it a more diffuse appearance (or bidirectional reflectance distribution function). ...
Museful's user avatar
  • 143
0 votes
1 answer
356 views

How can we generalize the definition a non-linear media?

According to the definition: Nonlinear media are dielectric materials whose polarization density changes nonlinearly if a strong field is applied to them. If the field is small the nonlinear terms ...
walber97's user avatar
  • 1,348
1 vote
0 answers
42 views

Extraordinary wave [closed]

In anisotropic media, for extraordinary wave, I don't understand how can the power flow not be in the same direction as the propagation. I can't find a physical intuition for it.
NAD's user avatar
  • 43
5 votes
1 answer
147 views

Difference between permittivities $\varepsilon_\text{opt}$ and $\varepsilon_\infty$?

Very often, in materials physics, we are interested in the relative permittivity at optical frequencies which is usually denoted by $\varepsilon_\text{opt}$ or $\varepsilon_\infty$. But I'm confused ...
BlueUpsilon's user avatar
1 vote
1 answer
35 views

Dielectric properties of polarizing beam splitter

Are all polarizing beam splitters made up of dielectric materials?If so, what kind of dielectric materials are actually used to make them?
Prakhar Dev Singh's user avatar
19 votes
1 answer
2k views

How can the refractive index be below 1 in a dielectric?

Upon checking the optical properties of different dielectrics, I found the interesting case of $Al_2O_3$. It seems to be reported with a refractive index below 1 in the infrared range of $10 - 12~\mu ...
DK2AX's user avatar
  • 4,788
6 votes
1 answer
293 views

Why is $\textbf{D}$ the response to $\textbf{E}$?

In the text Wooten, equation 2.69 shows $\textbf{D}$ being the response to $\textbf{E}$ with $\epsilon$ as the response function: $$ \textbf{D}(\textbf{r},t) = \int d\textbf{r}^{\prime} \int dt^{\...
von_sohn's user avatar