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2 votes
1 answer
132 views

Confusion about tensors in $SU(3)$

I have some confusion regarding the notion of tensors in $SU(3)$ (or some other matrix Lie group, but let's keep the discussion to $SU(3)$). For concreteness, I will refer to Peskin and Schroeder's ...
Quercus Robur's user avatar
0 votes
1 answer
93 views

Multiplying two $SO(3)$ representations

In Group Theory by Zee in Chapter IV.2, he discusses the multiplication of two $SO(3)$ representations on p. 207. Suppose you have a symmetric traceless tensor $S^{ij}$ which furnishes a $5$-...
mathemania's user avatar
1 vote
1 answer
81 views

Electromagnetic duality and vector/pseudovector transformation properties

One consequence of electromagnetic duality (see e.g., https://doi.org/10.1038/s41467-023-36420-4) is that if we have a system described by permittivity and permeability profile $(\varepsilon, \mu)(\...
daysofsnow's user avatar
2 votes
1 answer
202 views

Youngs' tableau method and its relation with tensors

During my masters my prof. mentioned that the Youngs' tableau method can be used to calculate the number independent components of any arbitrary rank symmetric tensor in arbitrary dimensions. I wasn't ...
Sagar K. Biswal's user avatar
-4 votes
1 answer
66 views

Cannot understand this identity between kronecker and metric tensor [closed]

I'm working on Lorentz generators and I am really not able to understand this relation: $$\omega_{\rho \sigma} \eta^{\rho\mu} \delta^{\alpha}_{\nu} = \frac{1}{2}\omega_{\rho \sigma} \left(\eta^{\rho\...
Heidegger's user avatar
  • 361
0 votes
0 answers
29 views

Unclear passage in Lorentz generators derivation

It's not clear to me a passage, in the extraction of the generators of Lorentz's group acting on the Minkowksi's space points: we have \begin{equation*} \begin{split} x^{' \alpha} & = \Lambda^{\...
Heidegger's user avatar
  • 361
0 votes
0 answers
55 views

Product of spherical tensors

Consider a spin $ j $ system. A spin $ j $ spherical tensor $ T^k_q(j) $ of rank $ k $ is a $ (2j+1) \times (2j+1) $ matrix. Given two spherical tensors of spin $ j $, say $ T^{k_1}_{q_1}(j) $ and $ T^...
Ian Gershon Teixeira's user avatar
0 votes
0 answers
54 views

Algebra equation for rank-3 tensor

Suppose I work in $4$ dimensions. I have an algebraic equation in the following form, which contains a rank-3 tensor $X ^{\alpha \lambda \mu }$ \begin{equation} X ^{\alpha \lambda \mu }\eta ^{\beta \...
A.D's user avatar
  • 1
0 votes
1 answer
213 views

How to get $3n-j$ symbols using the young tableau method?

How do one compute the $3n-j$ symbols using the young tableau method,for a $U(n)$ ? Edit $3j$ symbols were first introduced by Wiegner which are related to C.G. coefficients, similarly $6j$ symbols ...
Pradyuman's user avatar
  • 866
1 vote
1 answer
101 views

Question on the spinor Indices, in non-relativistic quantum mechanics

I've caught by a loop of: Standard texts of Non-Relativistic Quantum Mechanics $\to$ Representation theory of Lie groups and Lie algebras of $SO(3)$ and $SU(2)$ $\to$ Discussions of infinitesimal ...
BasicMathGuy's user avatar
1 vote
1 answer
68 views

Question on transformation law of spinors and the law $\xi^{\mu '} = D(L)^{\mu '}_{\nu}\xi^{\nu}$ where $D(L)$ is a representation of Lorentz group

In the reference $[1]$, the author presents the tensor quantities via its transformation laws. I'm pretty confortable with Pseudo-Riemannian geometry and tensors. But, when group theory enters the ...
M.N.Raia's user avatar
  • 3,085
2 votes
1 answer
260 views

Why is rank-3 tensor in 3D with two antisymmetric indices equivalent to rank-2 tensor?

I'd like to know how many irreducible representations of $SO(n)$ when it comes to rank 3 tensor. Here $n=3$. Among the rank 3 tensor components, there might be antisymmetric parts and symmetric parts ...
hwan's user avatar
  • 169
5 votes
2 answers
580 views

Are the linear Lie groups matrices, tensors, or both?

In some ways, this is a question about notation. In my experience, I have only seen the classical Lie groups — such as $\operatorname{GL}(n,\mathbb{R})$, $\operatorname{SL}(n,\mathbb{R})$, $\...
J Peterson's user avatar
2 votes
1 answer
83 views

From the point of view of physics, why is it useful to know the irreps of rotation group?

In 3D, the rank two tensorial physical quantities, for example, the electric susceptibility, the conductivity, the stress tensor etc, are in general, not irreducible representations i.e. neither ...
Solidification's user avatar
0 votes
1 answer
231 views

Tensor products in Howard Georgi's "Lie Algebras in Particle Physics"

My question is regarding eq.(3.39) in the second edition of Georgi's book (for those who have the book:)). The section deals with tensor product states where the states comprising the product ...
michelangelov's user avatar

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