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3 votes
2 answers
111 views

Does all symmetry breaking have corresponding unitary group?

In high energy physics. Symmetry breaking like electroweak's has corresponding $SU(2)\times U(1)$ unitary gauge group broken down to $U(1)$. Does it mean all kinds of symmetry breaking (even low ...
Jtl's user avatar
  • 425
2 votes
1 answer
42 views

Abelian vs non-abelian discrete symmetries in neutrino physics

I was reading about the parametrization of the PMNS matrix and stumbled upon an article of Serguey Petcov$^1$ about discrete flavour symmetries. It endeavors to see if there is a pattern induced by a ...
AZ0409's user avatar
  • 21
1 vote
2 answers
140 views

Why do representations of $SU(2)$ correspond to angular momentum eigenstates?

I have been learning about symmetry in one of my physics classes and specifically about $SU(2)$ and its irreducible representations. We can label a basis element of the vector space corresponding to a ...
Physics_Boss_India's user avatar
3 votes
0 answers
40 views

Gauging a finite non-abelian global symmetry in 2D

Consider a 2D system with a non-anomalous finite non-abelian global symmetry $G$, for example $$G = S_3=\{e,a,a^2,b,ab,a^2b\}$$ with $a^3=b^2=1$. One expects the local operators charged under the ...
JQ Skywalker's user avatar
1 vote
1 answer
87 views

Why are there triclinic and monoclinic lattices, but biclinic is never mentioned?

When classifying the Bravais lattices we have the triclinic (point group ${\rm C_i}$) and the monoclinic $({\rm C_{2h}})$ cases, but we do not see the "biclinic" case listed. Why not? It ...
Jos Bergervoet's user avatar
0 votes
2 answers
95 views

Conserved current transforming under adjoint

If we have a Lagrangian with a global internal symmetry $G$. Why do the conserved currents transform under the adjoint representation of $G$? Is it a general statement (if this is the case, how can we ...
Nathex's user avatar
  • 1
22 votes
2 answers
2k views

Have all the symmetries of the standard model of particle physics been found?

Background The standard model of particle physics is entirely determined by writing down its Lagrangian or, equivalently, writing down the corresponding system of PDEs. Every set of PDEs has a ...
William Wright's user avatar
1 vote
0 answers
83 views

QFT visual interpretation of $U(1)$

Anyone has (even a "pictorial") way of visualize what the group $U(1)$ does on the fields in the QFT framework? I know that $U(1)$ can be seen as a circle and the operation of the groups is ...
Lip's user avatar
  • 41
1 vote
0 answers
52 views

What kind of combinations of field components are equal under $SO(9)$ symmetry?

My question is a bit long and chaotic since I haven't learnt group theory systematically. I am looking at the Banks-Fischler-Shenker-Susskind (BFSS) matrix model. It consists of 9 bosonic matrices $...
Errorbar's user avatar
  • 368
0 votes
2 answers
71 views

A question from S. Weinberg's book (Sec. 2.7)

S. Weinberg in his book "The quantum theory of fields" page 82 says: the elements $T,\bar{T}$, etc, of the symmetry group may be represented on the physical Hilbert space by unitary ...
Mahtab's user avatar
  • 374
1 vote
1 answer
79 views

Lie group symmetry in Weinberg's QFT book

In Weinberg's QFT volume 1, section 2.2 and appendix 2.B discuss the Lie group symmetry in quantum mechanics and projective representation. In particular, it's shown in the appendix 2.B how a ...
liyiontheway's user avatar
0 votes
1 answer
62 views

Perturbation Theory with no symmetry breaking?

I was learing about group theory in QM and stable about symmetry breaking. I find it very interesting and search some stuff and even looked on wikipedia and found this: https://en.wikipedia.org/wiki/...
Alexandru Chirvasa's user avatar
2 votes
1 answer
158 views

Srednicki 36.5 symmetry question

This is from the intro to a problem 36.5 in Srednicki and not part of the problem itself. I am having trouble proving that $$\mathcal{L}=i\psi_j^\dagger\sigma^\mu\partial_\mu\psi_j$$ Has $U(N)$ ...
JohnA.'s user avatar
  • 1,713
2 votes
1 answer
216 views

What's the meaning of this path integral measure?

I don't understand the meaning of following path integral measure $$ \frac{[df]}{U(1)} $$ What is the difference between $[df]$ and $[df]/U(1)$? A naive idea is the latter measure is more physical ...
likai's user avatar
  • 53
15 votes
3 answers
3k views

Why do fields have to form a representation of the Lorentz group?

It is often claimed in quantum field theory texts that to have a sensible Lorentz invariant theory, the fields introduced must be in representations of the Lorentz group. This fact has always seemed ...
Leuca Patmore's user avatar

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