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2 votes
0 answers
35 views

A reference for the fact that the second cohomology of the full Poincare algebra is zero

S. Weinberg in his book "The quantum theory of fields" vol. I says in page 86 that the full Poincare algebra is not semi-simple but its central charges can be eliminated (as he showed in the ...
Mahtab's user avatar
  • 374
1 vote
0 answers
44 views

One-Loop beta function for gauge couplings

I am currently doing my homework on Standard Model one-loop correction. When I am reading Quantum Field Theory by Mark Srednicki and Journeys Beyond the Standard Model by Pierre Ramond, I notice some ...
quantumology's user avatar
3 votes
1 answer
58 views

Why semi-simple and compact Gauge Group in YM Theory? [duplicate]

I'm studying the Yang-Mills theory, with the Action: $$ S=-\frac{1}{2}\int\mathrm{tr}_{\rho}(\mathcal{F}\wedge\star\mathcal{F}) $$ where $\mathcal{F}:=\mathrm{d} \mathcal{A}+\frac{1}{2}[\mathcal{A},\...
BoyanLiu's user avatar
0 votes
1 answer
95 views

In QFT when performing path integral, why don’t we divide it by the volume of Poincaré group, as what we did for gauge group?

When performing path integral in gauge theory, we naively want to compute $$ Z = \int DA \exp(iS[A]) $$ But we noticed, that because the action is the same for gauge equivalent conditions, we should ...
zixuan feng's user avatar
1 vote
1 answer
79 views

Lie group symmetry in Weinberg's QFT book

In Weinberg's QFT volume 1, section 2.2 and appendix 2.B discuss the Lie group symmetry in quantum mechanics and projective representation. In particular, it's shown in the appendix 2.B how a ...
liyiontheway's user avatar
2 votes
0 answers
95 views

Why representations? [duplicate]

I've been studying Talagrand's What is a Quantum Field Theory? lately and I have some questions regarding the scheme he presents. Essentially the state of affairs as of where I am in the book is that ...
Lourenco Entrudo's user avatar
9 votes
6 answers
2k views

What exactly is a quantum field?

As I understand it, a relativistic quantum field is an operator-valued function of spacetime that transforms under some finite dimensional irreducible representation of the Lorentz* group: \begin{...
QFTheorist's user avatar
2 votes
1 answer
126 views

In what sense are fields representations of the Poincare group?

As far as I know, a representation is a homomorphism from the group to a vector space $V$ which preserves the group multiplication, i.e., if $(\pi,V)$ is a representation of the group $G$, then ...
QFTheorist's user avatar
2 votes
1 answer
216 views

What's the meaning of this path integral measure?

I don't understand the meaning of following path integral measure $$ \frac{[df]}{U(1)} $$ What is the difference between $[df]$ and $[df]/U(1)$? A naive idea is the latter measure is more physical ...
likai's user avatar
  • 53
0 votes
1 answer
127 views

Simple definition for the generator of an infinitesimal transformation

Studying quantum mechanics, or QFT, the concept of generator $G$ of an infinitesimal transformation $T$ keeps showing up. My problem is that I don't have in mind a solid (dare I say "rigorous&...
Noumeno's user avatar
  • 4,577
0 votes
0 answers
187 views

Represent the Pauli 4-vector $\sigma^\mu$ as hermitian matrix of matrices due to the $SL(2,C)$ universal double cover of $SO^+(3,1)$

It's known that it's possible to map a 4-vector $x^\mu=(t,x,y,z)$, here i use $c=1$, into a 2x2 hermitian matrix as linear combination of Pauli matrices, thus the mapping $x^\mu \leftrightarrow X$. ...
Cuntista's user avatar
  • 310
0 votes
0 answers
47 views

Why are the expressions of the Skyrme Model related with a kinetic and a mass term?

I was reading about the Syrme Model Lagrangian, $$ \mathcal{L} =-f^2_\pi/4 Tr(L_\mu L^\mu) + 1/32e^2 Tr([L_\mu,L_\nu]^2)- \frac{\mu^2}{2} Tr(1-U) $$ where $L_\mu=U^\dagger \partial_\mu U$. I've read ...
Gorga's user avatar
  • 161
3 votes
1 answer
112 views

Quantization of charge from the path integral

Consider a complex scalar field, with the usual Lagrangian: $$ \mathcal{L} = | \partial_{\mu} \phi|^2 - V(|\phi|^2). $$ This theory has a $U(1)$ symmetry, $\phi \to e^{i \alpha} \phi$, and the ...
Zack's user avatar
  • 3,098
1 vote
0 answers
76 views

Why do we need to consider the full Poincare group to get unitary representations?

I am trying to study and understand QFT from the perspective of symmetries. I was referred to this super helpful answer by @ACuriousMind : https://physics.stackexchange.com/a/174908/50583. I still ...
qavidfostertollace's user avatar
2 votes
1 answer
243 views

Some question about the irreducible representation of Poincare group

I am writing a note about the Poincare group and I am trying to explain that argument that one-particle state transforms under irreducible unitary representations of the Poincare group. However, there ...
David Shaw's user avatar

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