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5 votes
3 answers
666 views

How to see $\mathbf{E}\cdot\mathbf{B}$ is a total derivative?

Since $\mathbf{E}\cdot\mathbf{B}$ is a Lorentz invariant of the electromagnetic fields it seems like an interesting thing to plug into a Lagrangian to see what happens. However, this ends up ...
PPenguin's user avatar
  • 1,289
3 votes
2 answers
622 views

Gauge Invariant terms of Lagrangian for Electromagnetism

Besides the usual EM Lagrangian $\mathcal{L} = -\frac{1}{4}F^{\mu \nu}F_{\mu \nu}$, we can add an additional term $\mathcal{L'} = \epsilon_{\mu \nu \rho \sigma }F^{\mu \nu}F^{\rho \sigma} = -8 \vec{E} ...
Ricky Pang's user avatar
2 votes
1 answer
351 views

Hamilton's equations of motion on Dirac's formalism

I'm having several doubts about the procedure proposed by the Dirac-Bergmann algorithm in order to get the correct equations of motion of electrodynamics (Maxwell's equations). Suppose I've already ...
GaloisFan's user avatar
  • 1,742