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Why does an exact differential mean a force is conservative?
If you can express an integrand as an expression of just one variable i.e. $xdy + ydx = d(xy) = df$ then why does that mean that a loop integral on that will equal 0? Is it because if it is just a ...
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Path independence of a conservative force
My book Halliday et al. gives a proof of the path independence (conservative force). It is said that the net work to move a particle from a to b and then from b to a is zero. Thus the work done from a ...
user248666
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When calculating work in a line integral is the work done time independent?
The paramaterization of a curve when calculating the line integral is independent of the paramterization, it depends on path taken in the curve. My intuition is failing me, since it was said that by ...
user86411