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0 votes
1 answer
86 views

What are some ways to derive $\left( \boldsymbol{E}\cdot \boldsymbol{E} \right) \nabla =\frac{1}{2}\nabla \boldsymbol{E}^2$?

For each of the two reference books the constant equations are as follows: $$ \boldsymbol{E}\times \left( \nabla \times \boldsymbol{E} \right) =-\left( \boldsymbol{E}\cdot \nabla \right) \boldsymbol{E}...
Vancheers's user avatar
  • 105
0 votes
1 answer
38 views

Spherical and Cartesian forms of divergence [closed]

Suppose the electric field found in some region is $$\overrightarrow{E} = ar^3\vec{e}_r$$ in coordinates spherical (a is a constant). What is the charge density? So, using the spherical form of ...
Tassandro Cavalcante's user avatar
1 vote
1 answer
69 views

Calculating the divergence of static electric field without making the dependency argument?

This question is a follow up on this old post here Divergence of electric field (So this may seem dumb...) When calculating the divergence of a field point through the following equation, where $\left(...
P'bD_KU7B2's user avatar
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0 answers
38 views

Why is linear approximation of contribution of electric field the same as if whole charge was concentrated at a single point?

I was reading about electric field of uniformly charged ring, of radius $R$, on the axis of the ring at the distance $d$ from the center of the ring and I am confused about usage of differentials. It ...
LEM's user avatar
  • 21
0 votes
1 answer
172 views

The differential of a quantity

I often see the differentials of the electric field strength and the acceleration due to gravity being written as: $$dE= \mathcal{k}\frac{dQ}{r^2} \tag{1}$$ and $$dg=\frac{GdM}{r^2} \tag{2}$$ ...
Chern-Simons's user avatar
  • 1,047