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-1 votes
1 answer
103 views

How to Find Trajectory of Particle?

Let’s say I have a particle, and I know all the forces acting on it at every position. (Let’s say the particle is in an electric/gravitational field to simplify the mathematics involved.) Now, is ...
V T Naveen Mugundh's user avatar
0 votes
2 answers
68 views

Motion of free fall [duplicate]

We know that according to law of free falls object, all bodies fall with the same constant acceleration. But in distance formula ($s = \frac12 gt^2$), why the acceleration is just half?
Zeyar's user avatar
  • 25
3 votes
3 answers
848 views

How do you find the final velocity when acceleration is changing between two values over some distance? [duplicate]

How do you calculate a final velocity of an object when given its initial velocity and the object is accelerating between an initial and final acceleration over some given distance?
Tivity's user avatar
  • 287
2 votes
1 answer
200 views

How to use a piecewise acceleration function to get a position function?

This should be a relatively easy problem but I think I am missing something somewhere. This problem consists of a object that is being thrown into the air at $t = 4s$ at a velocity $v_0$ here is my ...
EzTheBoss 2's user avatar
0 votes
1 answer
273 views

Can position be derived from acceleration in practice?

We know that acceleration is the derivative of velocity, and velocity is the derivative of position. But does that mean that we can find position from acceleration in practice (as opposed to in theory ...
The Pointer's user avatar
3 votes
3 answers
357 views

Calculating displacement from acceleration (intuitively) [closed]

If I say acceleration of car is constant at $4\; \rm m/s^2$. Then isn’t it that it covers $4\; \rm m$ in $1\; \rm s$ with velocity $4\; \rm m/s$. Then in $2\; \rm s$, the velocity is $8\; \rm m/s$. ...
Srijan's user avatar
  • 725
12 votes
4 answers
3k views

Integrating acceleration - wrong choice of bounds in textbooks?

I've noticed in my physics textbook (and in a lot of other popular sources), that the process of integrating non-constant acceleration to get to a velocity formula, the integrating bounds imposed on ...
Ius Klesar's user avatar
0 votes
2 answers
42 views

Intuition of Distance covered when accelerating [duplicate]

When you're moving at $5$ m/s for $1$ second, you have traveled $5$ m. When you're moving at $5$ m/s (initial velocity) and you accelerate $2$ m/s for $1$ second, you have traveled $5$ m + $1$ m (...
austingae's user avatar
  • 163
-1 votes
1 answer
268 views

Integration of Acceleration to Get Delta Velocity

How do you get delta velocity if you have times t1 and t2 and their velocities v1 and v2, but you only know their accelerations a1 and a2. If you integrate over accelerations a1 and a2, do you get a "...
tomihasa's user avatar
0 votes
1 answer
95 views

Acceleration Question

I'm really confused how we have a distance formula from acceleration. I understand acceleration is the change of velocity/time, however I don't understand how you can calculate a distance based on a ...
Mike 's user avatar
  • 71
1 vote
2 answers
1k views

Why is there a $\frac{1}{2}$ in the kinematic equation? [duplicate]

In a few of the kinematic equations there is a $2$ or a $0.5$ coefficient. Why is this? For example the kinematic equation for distance is: $$\text{previous velocity} * \text{time} + \frac{1}{2} * \...
Philogy's user avatar
  • 115
2 votes
1 answer
3k views

Integrating an acceleration time graph gives you?

If I have a graph of Acceleration against time. Can I integrate this curve in order to find velocity and displacement?
Richard Woods's user avatar
5 votes
2 answers
2k views

Why does acceleration need to be constant if integrating?

My teacher wrote the following: Constant Acceleration If acceleration is constant, then: $$\vec{v}(t) = \int_0^t \vec{a}(t')dt'\ + \vec{v_0}$$ and $$\vec{x}(t) = \int_0^t \vec{v}(t')dt'\ + \vec{...
rb612's user avatar
  • 1,177
0 votes
4 answers
260 views

Explain $\Delta x = v_0t + \tfrac{1}{2}gt^2$ please? [duplicate]

$g = \Delta v/t$, so $\Delta v = gt$. $v = v_0 + \Delta v$, so $v = v_0 + gt$. So if $\Delta x = vt$, then $\Delta x$ should be $v_0t + gt$. Why the $\tfrac{1}{2}gt^2$? I'm really confused, so this ...
user3724492's user avatar
2 votes
3 answers
1k views

Basic question about acceleration [duplicate]

Very basic question. Please show where I'm wrong in the following reasoning. The movement of an object in function of time could be described as $$ x(t) = v t + x_{i} $$ if velocity is constant. If ...
Alex T's user avatar
  • 129

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