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Two trains A and B start from a station and move in parallel tracks with velocities 40 kmph and 60 kmph respectively. A man sitting in train A. watches a lady who walks inside the train B at a speed of 5 kmph opposite to the train's movement. What is the velocity of the lady according to the man?

I asked this to a few people, some say its 25kmph while others say its 15kmph. Could anyone please help?

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  • $\begingroup$ 15, because the speed of the lady is 55 kmph. $\endgroup$
    – Mahler
    Commented Jul 8 at 7:35

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Just draw a principal vector diagram of separate movements : enter image description here

Add $\vec B + \vec C = \vec C~'$ and you will get woman velocity relative to the ground. Now subtract that from train's A velocity vector and you will find woman relative velocity to the man, $\vec C~'-\vec A = \vec C~'_{man}$

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