6
$\begingroup$

I would imagine a material that is transparent but a electromagnetic wave going out will have a lower frequency than when going in (and maintaining it's direction). You could build glasses to see UV-light with that.

Has an effect like that been observed in nature? Could it theoretically be possible?

$\endgroup$
2
  • $\begingroup$ You can build a UV camera with a visible light monitor. $\endgroup$
    – mmesser314
    Commented Jun 28 at 12:57
  • $\begingroup$ You always lose coherence. The sun shining on your roof and it radiating heat onto you is a slow and decoupled down-conversion process. But it doesn't maintain the original coherence. $\endgroup$
    – Stian
    Commented Jun 28 at 22:33

2 Answers 2

10
$\begingroup$

Such a thing is possible in principle through the non-linear optical process of half-harmonic generation (and other processes of this class, generally known as photon downconversion).

Usually these non-linear optical processes are rather inefficient. For example, we can talk about the inverse of this process, second-harmonic generation. It is hard to estimate its efficiency because it varies wildly with the input power, but it seems like it may be around 6% for a one-watt infrared pump beam. This is high enough to actually have commercial uses, though. Second-harmonic generation is used to create green lasers. An infrared beam at $1064\,\mathrm{nm}$ is fed through a crystal of KDP, which converts some of the light to $532\,\mathrm{nm}$ green.

In your band of interest of UV, there are some additional considerations (see section "Generating Short Wavelengths") with regards to finding a suitable non-linear medium. But, there definitely are materials that have been used at these frequencies (see here). These examples are all about second-harmonic generation, the opposite of your UV-to-visible - but I think they capture the spirit of the question.

Even if you found a suitable material for downconversion of UV light, there are some issues you'd have in your specific application. One is that the power available in the ambient light field is simply too low. These non-linear effects generally require rather large power densities in order to be noticeable. All of that to say, that although there are indeed materials which have these properties, your specific application idea is infeasible.

$\endgroup$
2
  • $\begingroup$ Is high power density still required for step-down? For step-up, it makes sense that you need lots of photons to have a good chance for two to interact with an atom or molecule. But for step-down, hypothetically you just need one incoming photon to trigger the process that emits one or more photons of lower energy. If at least one of the visible-wavelength photons always goes in the same direction as the incoming photon, efficiency could be pretty high. $\endgroup$ Commented Jun 30 at 3:36
  • $\begingroup$ But in practice things are apparently far from that: in the paper @Maury linked - Passive frequency conversion of ultraviolet images into the visible using perovskite nanocrystals - we calculated that 0.4% of the ultraviolet photons incident on the film are ultimately converted into visible photons that are reemitted into free space, and After accounting for transmittances and numerical apertures for all optical components ... the expected system efficiency is approximately 0.001% (and their measurements agreed). $\endgroup$ Commented Jun 30 at 3:38
5
$\begingroup$

Yes, there are various materials that take two or more photons of long wavelength and produce one with a shorter wavelength, and vice versa.

An example of a "step up" material is KTP, which is used in the NIF laser to convert the original infrared laser output to green and then UV. This is more efficient than making a UV laser despite losses in the process.

The opposite direction, "downconversion" is also possible but generally more complex and still under development. But here is one example of doing precisely what you are asking, conversion of UV to visible, in this case green.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.