Imagine a rod (a rigid body) 10 meters long that is freely floating in space without being attached at any point. Its mass is 12 kilograms and according to most sources I found, its moment of inertia can be calculated via the following formula:
This makes its moment of inertia $100~\mathrm{kg}\,\mathrm{m}^2$.
If a perpendicular force of 24 newtons was constantly applied to its center (the 5-meter mark), its translational acceleration would be $2~\mathrm{m}\,\mathrm{s}^{-2}$ and angular acceleration would be $0~\mathrm{rad}\,\mathrm{s}^{-2}$. Now, if the same force was applied a distance $0.1~\mathrm{m}$ to the right of the center, there would be a torque of $2.4~\mathrm{N}\,\mathrm{m}$, and hence an angular acceleration of $0.024~\text{rad}\,\mathrm{s}^{-2}$. Similarly, if the same force is applied at the end of the rod (at 5 meters away from the center) the torque is 120 Nm and the angular acceleration is $1.2~\text{rad}\,\mathrm{s}^{-2}$
From this we can see that as the force is being applied further from the center, the angular acceleration increases due to more torque.
I was wondering if the linear (transitional) acceleration gradually decreases as the force is shifted away from the center (case 1), or does it abruptly become 0 when the force shifts even slightly away from the EXACT center of the rod (case 2).
If case 1 is true, how do you calculate the transitional acceleration?