If quantity $\vec q$ is a vector (like velocity, acceleration, force), then quantity $- \vec q$ is simply same vector $\vec q$ scaled by $-1$, so that now $$ -\vec q = \left[ \begin{matrix} -q_x\\
-q_y\\ -q_z
\end{matrix} \right]$$ column vector represents a reversed vector. You can see this easily if you draw some vector in $x,y$ plane for example, then invert it's components and see the result directly. Like here :
![enter image description here](https://cdn.statically.io/img/i.sstatic.net/kXd76Zb8.png)
vector $(5;2)$ is inverted version of vector $(-5;-2)$ or vice-versa. So to say negative vector quantity makes mirror reflection of positive vector quantity about $0$ point.
Now if some quantity is increasing or decreasing depends solely on a coordinate choice. So depending on how you choose $y$ coordinate major (positive) axis,- going down or up,- you will get ball thrown upwards speed balance equation at the terminal point $v_0-gt=0$ or $-v_0+gt=0$. These both forms are mathematically identical, since nobody can argue which coordinate system is best.
About retardation,- it's all relative. Imagine a rocket which already goes at some initial velocity $\vec v_0$, now it turns-on it's engines and starts to propel in reversed direction. Until it reaches zero speed you can name it "retardation", but if rocket will continue same trust,- deceleration will become acceleration. Hence deceleration is same acceleration, but towards $-x$ axis end instead of $+x$ axis end. So to say we have a vector and your task is to decide where "it is shooting at", i.e. choosing right and suitable coordinate system.
In case quantity is scalar and has differential form,- like for example decay rate for radioactive isotopes, $A=-dN/dt$. We can conclude from this if differential is increasing or decreasing. Here for example since number of radioactive isotopes decreases over time $dN$ must be negative. Multiplying it by $-1$ we get positive decay rate, which means average number of atoms decayed over unit time period.
HTH!