0
$\begingroup$

Is it possible to vary pressure of a given quantity of a gas without changing its volume by varying only temperature in real life? Why the varying temperature does not change the volume? Why the gas did not expand due increase in temperature? How exactly the volume of the gas is maintained to be constant? What does the textbooks actually mean by saying varying pressure without varying volume? In general, what my doubt is , how exactly we maintain one parameter to be constant by varying the remaining two?

$\endgroup$

2 Answers 2

4
$\begingroup$

The "full" answer depends on how complicated your model is.

The quick answer is: If your gas is trapped in a rigid container of fixed volume (like, say, a metal drum, or a thermos), if you increase the temperature of the gas by heating it, without changing the volume of the container, this will cause the pressure to increase. (Think of how a pressure cooker might explode from built-up pressure!)

Of course, in real life there's other factors such as (the relatively insignificant) thermal expansion of the vessel from the heat.

Edit: Assuming that the minute changes are negligible, a constant temperature can be achieved easily. Maintaining a constant pressure is certainly tricker!

$\endgroup$
1
  • $\begingroup$ Your answer could be improved with additional supporting information. Please edit to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers in the help center. $\endgroup$
    – Community Bot
    Commented Apr 12 at 9:16
0
$\begingroup$

Just look in your kitchen, humble pressure cooker! It's an isochoric (constant volume) system which utilizes heat energy to increase pressure inside it which in turn lifts the boiling point of water resulting in good heat transfer and increased rate of food preparation.

A piston (commonly used system for thermodynamic demonstrations) can also behave in similar way if it's made rigid and fixed.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.