I'm trying to understand how magnetic monopoles and how its potential mirror and antiparticle counterparts would behave. So according to the modified lorentz force law $$\vec{F}=q_e\left(\vec{E}+\frac{\vec{v}}{c} \times \vec{B}\right)+q_m\left(\vec{B}-\frac{\vec{v}}{c} \times \vec{E}\right)$$
Say a moving magnetic monopole that is deflected counterclockwise by an electron would be deflected clockwise by an positron.
$$E=\pm \frac{e}{4\pi\epsilon_{0}r^{2}}\hat{r}$$ So with small test positive monopole moving to the right azimuthally $\vec{v}=v\hat{\phi}$ it will experience a force downwards in the positive polar direction.
$\vec{F}=\mp \frac{q_{m}e}{4\pi \epsilon_0 c r^2}\hat{\theta}$
So we should have a mirror counterpart with opposite parity that experiences a force in the upwards negative polar direction in the same electric field.
So would the antiparticle of the magnetic monopole also have its parity reversed? In that case it would behave the same around the electron/positron since the opposite charge and parities would cancel out?