1
$\begingroup$

Would I still see the specimen but completely blurry? or wouldn't I see it at all? For example, let's say the wavelength of the light used is 600nm and the diameter of the specimen is 550nm.

Improve this question
$\endgroup$
1
  • $\begingroup$ It's called the diffraction limit. So diffraction,, so that sounds reasonable. $\endgroup$
    – DKNguyen
    Commented Mar 10 at 18:08

0

Reset to default

Browse other questions tagged or ask your own question.