I would like to know how to interpret the following force decomposition (Diagram (2)).
Diagram (1) is the typical force decomposition. Decomposing the force vector this way tells us about how much force is acting on the object ($F_1 = mgsin(\theta)$) to make it slide down the inclined plane and how much force is acting perpendicular to the surface ($F_2 = mgcos(\theta)$).
Now looking at Diagram (2) (assuming it has same inclined angle $\theta$), Force acting on ($-$x) axis is $F_1 = mg tan(\theta)$ and force acting perpendicular to the surface is now $F_2 = mg/cos(\theta)$.
Note: Both diagram's force $mg$ is decomposed such that when added it satisfies a parallelogram shape.
My question is how do we interpret such force decomposition in a physical way?
Diagram (1) is a situation where if you put an object of mass 'm' on a frictionless inclined plane it slides down. In Diagram (2), normal force increased and also force along x-direction increased. Meaning it would slide down faster than diagram (1) despite having same net force of $F_{net} = mg$.
Clearly, I am misunderstanding something. Can someone correct me where I am getting confused?