A typical statistical mechanics explanation for the probability ($p_i$) that a system (S) in contact with a reservoir (R) will take on a particular energy ($E_i$) is as follows (quoting from Greiner's textbook on the subject):
We ask for the probability $p_i$ of finding the system S in a certain microstate $i$ with the energy $E_i$. If S is a closed system, $p_i$ will be proportional to the number of microstates $\Omega_S(E_i)$. Analogously, $p_i$ is proportional to the number of microstates in the total closed system for which S lies in the microstate i with the energy $E_i$. Obviously this is just equal to the number of microstates of the heat bath for the energy $E - E_i$ , since S only assumes one microstate i:
$$p_i \propto \Omega_R(E_R) = \Omega_R(E_{total} - E_R)$$
But this is not "Obvious" to me at all since it seems to me that the total phase space (limited to a particular system energy $E_i$) will have additional degeneracy compared to the reservoir's phase space (limited to a particular reservoir energy $E_{total} - E_i$).
Consider the following minimal working example: Imagine a system comprising a single particle. The particle can only hold energy as x-direction momentum, so the system Hamiltonian is $p_{S,x}^2/2m$. Imagine the system is in thermal contact with a reservoir that has only two particles, each of which can only hold energy as x-direction momentum, so the reservoir Hamiltonian is $p_{R1,x}^2/2m + p_{R2x}^2/2m$ and the total system Hamiltonian is $p_{S,x}^2/2m+p_{R1,x}^2/2m + p_{R2x}^2/2m$. Energy of the total system is constant, of course. Then the phase space of the TOTAL system is visible as a 3D hollow spherical surface centered on the origin of the phase space axes $p_{S,x}$, $p_{R1,x}$, $p_{R2,x}$. Probability of the system being at any one location on this sphere is uniform. Thus surface area is proportional to probability. I'm trying to validate the truth of Greiner's textbook quote above by comparing the "surface area" on this phase-space sphere corresponding to a particular system energy $E_i$ (i.e., intersection of a plane at a particular value of $p_{S,x}$ with the sphere) to the "surface area" of the reservoir's phase-space (when reservoir has energy $E_{total} -E_i$). The curvature of the sphere creates a difference between the total system phase space and the reservoir's phase space, causing confusion to me, but I do see that "surface area" of phase space for single $E_i$ in this case has units of length rather than traditional length$^2$ units of area.
Is this a good example to consider? Does anyone know of a better way of understanding it more clearly / intuitively?