In the framework of Quantum Physics, I have to explain to some of my colleagues what is a Lie group, a Lie algebra and their connections with the exponential map. This is mainly to make them understand the mathematical background behind Pauli matrices and the fact that they generates $SU(2)$.
I googled "Lie group" with "generators", along with "integral curves" and "tangent space" to understand how to present in a general form the link between Lie groups and algebras. But the mathematical formulation is mostly too far from my background and that of my colleagues.
So, I would like to start from a matrix Lie group $G$ parameterized by $\vec{a}=(a_1,\dots,a_p)^t\in\mathbb{R}^p$ such that: \begin{equation} M(\vec{a}+\vec{b})=M(\vec{a})M(\vec{b})\;,\quad M(\vec{0})=I\;, \quad M(-\vec{a}) = [M(\vec{a})]^{-1} \end{equation}
with $M(\vec{a})$ a $n\times n$ matrix belonging to $G$.
As far as I understood the many online available tutorials on Lie groups, one way to develop the link between Lie groups and algebras is to exhibit the tangent space at the Lie group neutral element ($I$) through integral curves.
So, first I define a one parameter curve within the Lie group: \begin{equation} \begin{split} \mathbb{R}&\mapsto G\\ t &\mapsto M(t)=M(\vec{a}(t)) \end{split} \end{equation} such that $M(0)=I$. Then the key point is that the Lie group parameters $\vec{a}$ are function of $t$.
This curve is an integral curve means it complies to: \begin{equation}\label{eq:0} M(t+h)=M(t)M(h) \end{equation} Then, by deriving this equation, one gets : \begin{equation} \frac{\,d M}{\,dt}=\frac{\,d M(t)}{\,dt}\biggl|_0 M(t) \end{equation} then: \begin{equation} M(t) = e^{m t} \end{equation} with \begin{equation} m=\frac{\,d M(t)}{\,dt}\bigg|_0 = \sum_{i=1}^p \frac{\partial M}{\partial a_i}\bigg|_0\frac{\,d a_i}{\,dt}\bigg|_0 = \vec{\sigma}\cdot\vec{n} \end{equation} where \begin{equation} \vec{\sigma}=\biggl(\frac{\partial M}{\partial a_1}\bigg|_0, \dots, \frac{\partial M}{\partial a_p}\bigg|_0 \biggr)^t \end{equation} is the a vector of matrices called the infinitesimal generators of $G$, through the exponential map. They form a basis for the tangent space of $G$ at $I$, which happens to be also a Lie algebra.
This is what I am able to understand, but there are several obscure points for me:
what is the meaning of the derivatives $\frac{\,d a_i}{\,dt}$?
integral curve: the equality $M(t+h)=M(t)M(h)$ implies that $\vec{a}(t+h)=\vec{a}(t)+\vec{a}(h)$, which has no reason to occur unless there are some specific assumptions. As far as I understand this assumption it that the curve be integral. Could you help me to demonstrate clearly how this holds?
in tutorials, this demonstration makes use of the "left invariant" of $G$, I am unable to give this notion its right place here.
is my demonstration correct ? I know that the Lie algebra only generates the connected to unity ($I$) part of $G$. But here, this seems apply to any element of $G$? or maybe the integral curve notion guarantees that $M(t)$ is connected to $I$?
also, I read several times that one-parameter subgroups of $G$ are always of this kind, what does it mean exactly?
I would be grateful to you if you could give me some more insights about this, so that I can make this clear to my colleagues too.