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There's an interesting exercise (page 13, Exercise 11) in Hugo Duminil-Copin's Lectures on the Ising and Potts models on the hypercubic lattice, which states that the following 2 statements are equivalent for strictly positive measures on $\{0,1\}^E$ where $E$ is a finite set of edges

  1. $\mu'[\omega \vee \omega'] \mu[\omega \wedge \omega'] \ge \mu'[\omega'] \mu[\omega]$ for all $\omega,\omega'$ where $\vee,\wedge$ denotes taking the component-wise max, min.
  2. $\mu[\omega_e=1|\omega_{E\backslash e}=\psi] \le \mu'[\omega_e=1|\omega_{E\backslash e}=\psi']$ for all edges $e\in E$ and $\psi \le \psi'$ (edge-wise comparison)

It's clear that condition 1 implies condition 2, but I'm confused on how one would show that condition 2 implies condition 1. Any insights would be appreciated!

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    $\begingroup$ The equivalence is proved, for instance, in this book, Theorem 2.24. $\endgroup$ Commented Mar 14, 2023 at 17:59

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