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I was reading Classical Mechanics : The theoretical minimum by Leonard Susskind, and he says

Assume that two clocks at different places can be synchronised.

I don't understand why one should do that. Can't one clock at the origin be enough? Whenever I try to start on special relativity, this crops up. Can someone explain this to me or at least point me towards any resources which explain such issues in detail? Especially special relativity related.

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    $\begingroup$ If you read the sentences/sections immediately after a second clock is introduced, it should be immediately clear why it was introduced. $\endgroup$
    – Kyle Kanos
    Commented Jan 19, 2023 at 15:24
  • $\begingroup$ @KyleKanos Do you mean in general in any book? $\endgroup$ Commented Jan 19, 2023 at 15:25
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    $\begingroup$ Correct. Any book that covers relativity should make it clear why there are 2 clocks if you read a little further. $\endgroup$
    – Kyle Kanos
    Commented Jan 19, 2023 at 15:26
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    $\begingroup$ Can the question whether two clocks run at the same rate make any sense without synchronizing them first? $\endgroup$
    – hyportnex
    Commented Jan 19, 2023 at 15:41
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    $\begingroup$ If you think carefully, any mental picture using only one clock is implicitly assuming a relationship between "time at point A" and "time at point B." You cannot compare spatially separated events without defining a clock synchronization strategy. See "Clock Postulate" $\endgroup$
    – RC_23
    Commented Jan 19, 2023 at 16:34

3 Answers 3

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All of special relativity is based on the assumption that any observer can set up a coordinate system and then label spacetime events with their coordinates in that system. Then we can use the Lorentz transformations to transform between the coordinate systems of different observers.

The positions of events are easy because I have an infinite number of rulers and simply by laying them one after the other I can create a grid that fills all of spacetime. Then when some event happens my colleague who happened to be standing where the event happened can just look at my rulers and note down the position.

But the time is trickier. Time measurements are easy for events at my position because I just look at my clock and note the time. But for any distant event I have to ask my colleague next to the event to note the time on their clock. I could wait for the light from the event to reach me, and subtract off the travel time to get the original time of the event, but this is now an indirect measurement of the time. This workable in SR, but in GR light travel times are impossible to calculate unless I know the exact trajectory the light took, and indeed the light could reach me by multiple paths as happens in gravitational lensing.

So the only safe option is to put a clock at each point of my grid of rulers then synchronise them all. That way the event coordinates can be recorded by a colleague standing at that point. But this only works if all the clocks can be synchronised, and this is harder that it appears at first sight. If I move my clock to yours so we can synchronise them my clock will be time dilated by the motion and this spoils the timing. That's why we resort to protocols like Einstein synchronisation.

Now this is all conceptual rather than realistic and we clearly don't actually measure events this way. However it is a concept that is at the heart of special relativity, and that's why books on SR tend to labour the point.

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  • $\begingroup$ Thank you. But a new doubt - how do we know space/time is uniform in a given reference frame? I see it mentioned as a requirement, but how can it be verified experimentally and what does it really mean? I am asking because I have a vague sense that synchronizing clocks isn't enough, what if they don't run at the same rate due to them being at different places or something? I myself am not clear what I am asking, if you didn't get an inkling of the meaning of my question, it's because I myself am not clear what the issue is. $\endgroup$ Commented Jan 19, 2023 at 19:12
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    $\begingroup$ @NeeladriReddy Special relativity is the theory of flat spacetime so the spacetime is uniform by definition. If we move to GR then the meaning of a coordinate system becomes more complicated. In general we can't synchronise clocks in GR, and even if we did they wouldn't stay synchronised. $\endgroup$ Commented Jan 19, 2023 at 20:12
  • $\begingroup$ "The positions of events are easy": No. Distances also change depending on the observer. The same point in space and time translates to a different position and different time depending on the speed of the observer. Also, what is "here" in the future depends on the speed of the observer. $\endgroup$
    – Florian F
    Commented Jan 20, 2023 at 11:51
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    $\begingroup$ @FlorianF all measurements are being made in my inertial frame. $\endgroup$ Commented Jan 20, 2023 at 12:18
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    $\begingroup$ @FlorianF, Moving a ruler does not permanently change its length. I perceive it to have a different length while it is in motion, but once I have finished laying down my grid of rulers, I can trust that they all have the same length (even the ones that I placed in the far distance) so long as none of them is moving with respect to me. Clocks are slightly different. Moving a clock does not permanently change the rate at which it ticks, but the temporary slowdown that i perceive while moving it out to a distant location does permanently change its "offset" from my time origin. $\endgroup$ Commented Jan 21, 2023 at 14:30
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Two clocks are required to show that the time and place where an event occurs is relative to the two observers (one moving and one stationary), even if the two clocks were synchronized in the first place. This is usually expressed using the Lorentz transformation, \begin{align} t' &= \gamma\left(t-vx/c^2\right) \\ x' &= \gamma(x-vt) \end{align} where $(x,\,t)$ are the coordinates in the stationary frame, $(x',\,t')$ the coordinates in the moving frame (moving with velocity $v$) and $\gamma^2=1/(1-v^2/c^2)$.

For an arbitrary time $t>0$, we find that $(x,\,t)$ and $(x',\,t')$ have different values, indicating that each of the two observers sees the same event happening at a different time and place as the other observer. Hence, two clocks would be required to analyze the scenarios, rather than a single one.

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When we want to compare clocks, there must be a method to compare them. Since time is not absolute in relativity theory, different observers will disagree on what events they consider simultaneous. So comparing clocks is no longer unambiguous.

To be able to compare clocks, therefore, we must have a method that yields the same outcome for all observers, regardless of these observers’ own motions. This is clock synchronization.

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