According to this article about the Alcubierre metric, the metric can be transformed in a way that results in "spherical symmetry" about the x-axis. I have to assume they meant to say cylindrical instead of spherical here. But even without transforming to $r=x-vt$, I believe this is evident when transforming $y$ and $z$ to $p=\sqrt{y^2+z^2}$ and $\phi=arctan(\frac{z}{y})$, so I have to wonder if there is some other killing vector made apparent by transforming to $r$. Furthermore, if after transforming to $r$, I transform to a comoving time coordinate $n$ which eliminates the diagonal, would $g_{nn}dn$ be a killing vector?
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$\begingroup$ Minor comment to the post (v1): Please consider to mention explicitly author, title, etc. of link, so it is possible to reconstruct link in case of link rot. $\endgroup$– Qmechanic ♦Commented Nov 25, 2022 at 20:01
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