For an inductor in a circuit without a power source, does the induced emf found by using the mutual inductance value include self inductance, or is the self induced emf considered separately?
From Faraday's law I know that the induced emf is found by considering the total flux, and that this is equal to the self induced emf for the case where the inductor is connected to an external power source. For the emf induced by mutual inductance, the flux through the inductor is considered to be the flux due to the external inductor, but not the total flux, which leads me to think that there should be an added term in order to calculate the total induced emf. However, I do realize this could lead to doubly counting the flux produced by the self induced emf since this flux also affects the current in the inductor producing the external flux, which is already included in the calculation. But wouldn't this violate Faraday's law?