I'm trying to verify the E.M potential energy $U= \int{A_\mu J^\mu} = q(\phi - A_j v^j )$ by using the connection: $$ F= - \frac{\partial U}{\partial r} + \frac{d}{dt} \frac{\partial U}{\partial v} $$ with $F=q(E+v \times B)$.
I seem to have some extra term.
We work in units where $q=1$.
The L.H.S: $$ F_i=E_i + (v \times B)_i = E_i + \epsilon_{ijk} v_j B_k = \\= - \frac{\partial \phi}{\partial r^i}-\dot{A}_i + \epsilon_{kij} \cdot v_j \cdot \epsilon_{klm}\partial_lA_m = \\ = - \frac{\partial \phi}{\partial r^i}-\dot{A}_i + v_j \partial_lA_m \cdot \left( \delta^l_i \delta^m_j - \delta^m_i \delta^l_j \right) = \\ = - \frac{\partial \phi}{\partial r^i}-\dot{A}_i + v_j \partial_i A_j - v_j \partial_jA_i . $$
Now, the last term is:
$$ v_j \partial_jA_i= \frac{dr^j}{dt} \frac{ \partial A^i}{\partial r^j }= \frac{dA_i}{dt} = \dot{A_i} $$
So we get the L.H.S: $$ - \frac{\partial \phi}{\partial r^i}-\dot{A}_i + v_j \partial_i A_j - \dot{A_i} $$
The R.H.S (first term):
$$ - \frac{\partial U}{\partial r^i} = - \frac{\partial (\phi-A_j v_j )}{\partial r^i} \\ = - \frac{\partial \phi}{\partial r^i} + v_j \partial_i A_j $$
The R.H.S (second term):
$$ \frac{d}{dt} \frac{\partial U}{\partial v^i} = \frac{d}{dt} \frac{\partial }{\partial v^i} \left( -A_j v_j \right) = -\frac{d}{dt} \left( A_i \right) = -\dot{A}_i $$
So the R.H.S gives: $$ - \frac{\partial \phi}{\partial r^i} + v_j \partial_i A_j -\dot{A}_i $$
and there is a $-\dot{A}_i$ term difference. What am I missing?