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How will the electric current in this circuit flow? Assuming that the current starts flowing from the positive(+ve) terminal (Conventional current), will it flow entirely through the branch between the 2Ω and the 1Ω resistor offering no resistance {Ideal} or will it flow through both the paths{Through the middle branch and the 1Ω resistor}? and if it flows through both paths, then why is that the case? Current as far as I know, prefers a path which offers the least resistance. In this case, shouldn't it pass entirely through the middle branch with no resistance?

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    $\begingroup$ Is there a connection where the two lines cross at the center? And where is the reference node? $\endgroup$
    – The Photon
    Commented Jun 22, 2022 at 4:16
  • $\begingroup$ There is no connection between the two lines crossing at the centre. $\endgroup$
    – LuciferP
    Commented Jun 22, 2022 at 4:21
  • $\begingroup$ Consider the potential at the positive terminal "V" and the potential at the other terminal 0. $\endgroup$
    – LuciferP
    Commented Jun 22, 2022 at 4:25
  • $\begingroup$ This question might be silly but I am confused. Maybe, I'm lacking some important concepts. $\endgroup$
    – LuciferP
    Commented Jun 22, 2022 at 4:31
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    $\begingroup$ Try redrawing the circuit with no crossings, then it will be much easier to analyze. $\endgroup$
    – The Photon
    Commented Jun 22, 2022 at 4:33

1 Answer 1

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It's a multi step process:

  1. Redraw the circuit without the crossing traces.
  2. Add a trace, see which resistances are shorted out, and then redraw without those resistances.
  3. Repeat step 2 for the last trace.

At the end of process, the actual path the electrons take will become clear

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