I just stumbled across the problem and have no idea how to solve it: "Considering the Time-Independent Schrodinger Equation for a stationary state $\psi$ with energy $E$, that is $$\psi '' = \frac{2m}{\hbar ^2 }(V(x)-E)\psi,$$ prove that $E$ must exceed the minimum value of the potential, by noting that $E=\left\langle H \right\rangle $"
My attempt:
We assume firstly that $E<\min(V(x))$, and thus $V(x)-E>0$ for all $x$. Thus if define $\frac{2m}{\hbar ^2 }(V(x)-E) = A(x)>0$, as all the terms in the function are positive, we get: $$\psi '' = A(x)\psi$$ Since $A(x)>0$, we know that $\psi ''$ and $\psi$ have the same sign. I don't know where to go from here. Haven't even used the fact that $E=\left\langle H \right\rangle $. Any help would be appreciated!