Now we know that charge q will also produce an electric field. Due to this field, the field already present in the space should be modify.
Yes, the total electric field has contribution due to the charged particle, in the sense that at all points where total field is defined, its value is different than it would be if the particle wasn't there.
However, modifying the standard equation
$$
\mathbf F_{electric~on~particle~a} = q_a\mathbf E_{ext}(\mathbf r_a)
$$
which is the basis for experimental definition of external electric field at any given point, into
$$
\mathbf F_{electric~on~particle~a} = q_a\mathbf E_{total}(\mathbf r_a)
$$
is not warranted.
Why? In case the particle is a point, its field diverges when approaching that point and has no meaningful value at that point - so total field is not defined at that point either. So the second equation would be meaningless.
In case the particle is a ball or sphere or other extended body with finite charge density, total field is defined everywhere, but its has different directions at different parts of the particle. So the equation doesn't really look like the second one above, but more like
$$
\mathbf F_{electric~on~particle~a} = \int \rho_a(\mathbf r_a + \mathbf x') \mathbf E_{total}(\mathbf r_a+\mathbf x')\,d^3\mathbf x'
$$
where the integration goes over region containing the whole particle. We can integrate all those little parts and get net electromagnetic self-force as a function of internal structure of the particle, its position and all position derivatives, but only approximately.
This was done by Abraham and Lorentz at the beginning of 20th century. The resulting self-force dependence on position derivatives is complicated, but it has two interesting properties:
there is a component of self-force of the form $-\mu_{EM} \mathbf a$ where $\mu_{EM}$ is some positive constant factor, which for single sign charge distribution depends on total charge and its distribution (size of the particle) and $\mathbf a$ is acceleration of the particle; this effectively increases inertial mass of the particle;
there is component of self-force of the form $k\dot{\mathbf a}$ where $k$ is a positive prefactor that depends only on total charge, it doesn't depend on the size of the particle.
So the equation this leads is something like
$$
\mathbf F_{electric~on~particle~a} = q_a\mathbf E_{ext}(\mathbf r_a) - \mu_{EM} \mathbf a + k \dot{\mathbf a}~+ $$
$$+~\text{other terms depending on motion of the particle}.
$$
Effects similar to those of the two additional terms are observed in reality in macroscopic coils and emitting antennas: in coils, increased effective mass of electrons due to mutual interaction between all the accelerating electrons is responsible for the effect of self-inductance; and in an emitting antenna, in addition to the first effect, the force $k\dot{\mathbf a}$ for oscillating current behaves as a friction force $-k\omega^2 \mathbf v$, so this is the force of radiation resistance, sucking energy away from the antenna.