I would like to ask you a question - maybe simple - but bothering me.
We have two four-position vectors product in curvilinear coordinates given by
$(1) \quad X^{\alpha}g_{\alpha \beta}X^{\beta} = \tau^2$
and taking proper-time derivative I expected to get
$(2) \quad 2\cdot U^{\alpha}g_{\alpha \beta}X^{\beta} = 2\tau$
But if we would decompose it into partial derivatives and proper-time derivatives of separate vectors it would be:
$(3) \quad \frac{dX^{\alpha}}{d\tau}g_{\alpha \beta}X^{\beta} + X^{\alpha}g_{\alpha \beta}\frac{dX^{\beta}}{d\tau} + X^{\alpha}X^{\beta}\frac{dg_{\alpha \beta}}{d\tau} = 2\cdot U^{\alpha}g_{\alpha \beta}X^{\beta} +X^{\alpha}X^{\beta}\frac{dg_{\alpha \beta}}{d\tau} \neq 2\tau$
$(4) \quad U^{\gamma} \nabla_{\gamma} X^{\alpha}X^{\beta}g_{\alpha \beta}= U^{\gamma} g_{\gamma}\,^{ \alpha} X^{\beta}g_{\alpha \beta} + U^{\gamma} g_{\gamma}\,^{\beta} X^{\alpha}g_{\alpha \beta} + X^{\alpha}X^{\beta} U^{\gamma} \nabla_{\gamma} \, g_{\alpha \beta} = 2\cdot U^{\alpha}g_{\alpha \beta}X^{\beta} +X^{\alpha}X^{\beta}U^{\gamma} \,[??] \neq 2\tau $
What is bothering me is that:
A) $Eq (2) \neq Eq (3) \neq Eq (3)$
B) If equation (2) is correct, then why? Because metric tensor may be changing over time as I suppose.
C) What it is $[??]=\nabla_{\gamma} \, g_{\alpha \beta} $ in Eq. (4)? - As far as I know, metric tensor should be invariant under covariant four-gradient, and therefore I have no idea what is the result of such derivative.
I would appreciate if you find a while to answer.
I suppose for you it will be a minute, but I have really doubt about above formulas.