The condition for a current being induced in such a loop is that the magnetic flux changes with time. If the loop is fixed and is submitted to a constant magnetic field, there will be no induced current. Look at Faraday's Law:
$$ \oint E \cdot dl = - \frac{\partial \phi_{m}}{\partial t} \; , \phi_{m} = \vec{B} \cdot \vec{A}$$
If neither the magnitude of the magnetic field, nor the magnitude of the area, nor the angle between the magnetic field vector and the area vector, changes, there won't be an induced voltage and hence there won't be an induced current.
Furthermore, even though you change the magnetic flux, creating such an induced current, the value of the current will not be constant. As soon as you stop changing the magnetic flux, the induced voltage will go to 0 and hence the induced current as well. The induced Electric Field is said to be non-electrostatic, which in our context means that there won't be a constant current.
Finally, the Force equation that you have written is only valid for point charges. The magnetic force given by $F_{m} = q(\vec{v} \times \vec{B})$ is associated with moving point charges. Extense bodies such as a loop, a rod, a big wire, etc, have magnetic forces that are calculated differently.
"I agree with the fact that the equation that I gave for the force is only for a point charge, but it was to illustrate my problem, which is: in my situation, how do I compute the force on the loop, is there any electric field that I need to worry about? I forget to say that the loop has a null self inductance."
![enter image description here](https://cdn.statically.io/img/i.sstatic.net/4ZBfB.jpg)
As you can see in the image, you are able to split your loop into segments such as you can treat these segments as current-carrying wires, and use the magnetic force formula for this case that is: $F_{m} = I(\vec{L} \times \vec{B})$. Use the right-hand rule to find the correct directions and perform a vector sum.
If you change the magnetic flux and create an induced non-electrostatic electric field that will generate an induced current, you will need to take into account that this induced current, by Lenz's law, will be in such a way that it will create a contrary magnetic field that will act opposed to the magnetic field that the loop is submitted. That may change the net magnetic field and therefore the net magnetic force.
Hope I have answered your question, have a nice day!