It should be a very fundamental thing, a very simple question. But there's something I want to understand.
We know that when we throw an apple vertically upwards, it experiences a force of gravity due to the Earth, and in turn, the Earth also experiences a force acting on it, equal in magnitude. That's what Newton's 3rd law says would happen. Although the acceleration of apple towards the Earth is much largerer (because of its must smaller mass compared to Earth's) than the rate at which Earth accelerates towards the Apple. Earth's acceleration is negligible, but it is not zero.
Here's what I want to understand. Since motion is always relative, what if I am asked this question : Apple's and Earth's accelerations are with respect to which observer (or which reference frame)?
I could say that the Apple accelerates with respect to the Earth's reference frame. Because when we consider the acceleration of the Apple relative to Earth, we assume that Earth is at rest even if it is moving (relative motion). Similar to
$a_{AB}$ $=$ $a_A$ $-$ $a_B$
Here $B$ is observing $A$ and $B$ is treated to be at rest (relative to Earth) even though $B$ has its own acceleration, its acceleration is added to $A$ with a negative sign.
So I could say that the Apple is accelerating at whatever rate it is accelerating at, $relative$ to $Earth's$ reference frame. What about Earth's acceleration? I can't say that the earth is accelerating relative to the Apple because in that case its acceleration would be equal to Apple's acceleration with a minus sign. So the Earth accelerates relative to which frame? Also, is it correct to say the Apple is accelerating relative to Earth's frame (just want to confirm).