I gather that Bohm denies the notion that the act of measurement decides whether a photon will be a wave or a particle. Bohm's idea seems to be that the photon is always a particle with a real trajectory that always passes through one OR the other slit, NOT bizarrely through both slits simultaneously, in the double-slit experiment. The photon, Bohm says, also has a "pilot wave" that causes the photon to land on a photographic detecting plate according to an interference pattern (which pattern shows up on the plate after the physicists fire off, one at a time, a sufficient number of photons).
My question: if the photon always has Bohm's pilot wave, and if both the photon itself and its pilot wave objectively exist prior to and independent of measurement and detection, then how does Bohm explain the lack of any interference pattern when the double-slit experiment is set up to detect not waves but particles? I gather that when the physicists set up the double-slit experiment to detect a particle, and the physicists fire off one photon at a time toward the double slit barrier, then after enough photons have been fired off, the result on the detecting photographic plate is NOT an interference pattern, but only two bands of light corresponding to the two slits, just as one would expect if light were corpuscular. In other words, no indication of wave behavior, which means no indication of Bohm's pilot wave. If, as Bohm says, the photon is always a real particle that has a pilot wave that really exists objectively, prior to and independent of measurement or detection, shouldn't an interference pattern ALWAYS show up with the two slit experiment (after enough photons have been fired off), even when physicists set up the experiment to detect particles, not waves?
If possible, explain your answer without assuming I have any knowledge of physics. Thanks very much.