The definition of electric potential is the work done per unit charge in moving the charge from infinity to that distance.
Now, from Coulomb's law, $$F = \frac{KQ_1Q_2}{r^2}.$$ So we can now rearrange for the electric field strength: $$\frac{F}{Q_1}=\frac{KQ_2}{r^2}.$$
The next bit is where my confusion lies. To get the electric potential equation, we must multiply by $r$ to get $F r = W$.
But is this not the distance away from the charge and the work done in moving the charge through that distance, as opposed to the distance from infinity?