I am following the procedure outlined in the book "Spacetime and Geometry" by Carroll. The objective is to transform a tensor. In the book, he has this example:
We have a (0,2) tensor of the following form: \begin{equation} S_{\mu \nu}= \left( \begin{array}{cc} 1 & 0\\ 0 & x^2 \end{array} \right) \end{equation}
We impose the following change of coordinates: \begin{equation} x' = \frac{2 x}{y} \end{equation} \begin{equation} y' = \frac{y}{2} \end{equation} which we can invert to give: \begin{equation} x = x'y' \end{equation} \begin{equation} y = 2y' \end{equation} We also have the following transformation relation for a tensor: \begin{equation} T^{\mu_1'\dots\mu_k'}_{\;\;\;\;\;\;\;\;\nu_1'\dots\nu_b' } = \frac{\partial x^{\mu_1'}}{\partial x^{\mu_1}}\dots \frac{\partial x^{\mu_k'}}{\partial x^{\mu_k}}\frac{\partial x^{\nu_1}}{\partial x^{\nu_1'}}\dots\frac{\partial x^{\nu_b}}{\partial x^{\nu_b'}}T^{\mu_1\dots\mu_k}_{\;\;\;\;\;\;\;\;\nu_1\dots\nu_b } \end{equation} In the book, he obtains the answer using another method, but says the reader should check to see that using this transformation equation will yield the same answer. So this is what I did.
So first off, in this case, $k=1$ and $b=1$, so we have : \begin{equation} T^{\mu'}_{\;\;\nu'}=\frac{\partial x^{\mu'}}{\partial x^{\mu}} \frac{\partial x^{\nu}}{\partial x^{\nu'}} T^{\mu}_{\;\;\nu} \end{equation} Also in our case, we have a (0,2) tensor, while this is a (1,1) tensor. So we need to lower $\mu$. \begin{equation} T_{\mu\nu}=\eta_{\mu\sigma}T^{\sigma}_{\;\;\nu} \end{equation} I don't think this has any bearing on the transformation equation. We have: \begin{equation} \frac{\partial x^{\nu}}{\partial x^{\nu'}} = \left( \begin{array}{cc} y' & x'\\ 0 & 2 \end{array} \right) \end{equation} \begin{equation} \frac{\partial x^{\mu'}}{\partial x^{\mu}} = \left( \begin{array}{cc} \frac{2}{y} & \frac{-2x}{y^2}\\ 0 & \frac{1}{2} \end{array} \right) \end{equation}
This is where I get confused. These matrices are not in the same terms. One is in primed coordinates and one is in unprimed coordinates. I am guessing I just write everything in terms of primed coordinates, meaning I would get:
\begin{equation} S_{\mu'\nu'}= \left( \begin{array}{cc} \frac{1}{y'} & \frac{-x'}{2y'}\\ 0 & \frac{1}{2} \end{array} \right) \left( \begin{array}{cc} 1 & 0\\ 0 & (x'y')^2 \end{array} \right) \left( \begin{array}{cc} y' & x'\\ 0 & 2 \end{array} \right) \end{equation}
where the center matrix is just $S_{\mu\nu}$. This gives me: \begin{equation} S_{\mu'\nu'}= \left( \begin{array}{cc} 1 & 0\\ 0 & (x'y')^2 \end{array} \right) \end{equation}
Which is just $S_{\mu\nu}$ and not the right answer. The right answer is: \begin{equation} S_{\mu'\nu'}= \left( \begin{array}{cc} (y')^2 & x'y'\\ x'y' & (x')^2+4(x'y')^2 \end{array} \right) \end{equation}
Where did I go wrong?????? What am I not getting??