Monochromatic light passes through a double-slit arrangement. The intensity of the monochromatic light passing through one of the slits of the double-slit arrangement is reduced. State, and explain, the effect of this change on the appearance of the bright fringes and of the dark fringes.
It makes sense that the brighter fringes will reduce in brightness due to the fact that the sum of the amplitudes will not be as high a number as before.
However, I'm a little confused as for the effect on the appearance of darker fringes. I thought that because darker fringes means 0 light intensity, I thought that even after the reduction in intensity of the monochromatic light, destructive interference will still take place at some point, therefore giving rise to no change in appearance to the dark fringes.
However, the answer to the above question says "dark fringes will be brighter / less dark because summing amplitudes no longer gives zero"
Could someone please explain the flaw in my conceptual understanding?