14
$\begingroup$

If earth assembled out of space dust, how come we find heavy elements like gold, silver, uranium and bunch of others that are heavier than iron on the surface?
I mean silicon (Si mass 28.084) being the crust makes perfect sense as it is lighter than iron (Fe mass 55.845).
Shouldn't heavy elements been sank by gravity to the 'bottom' of the Earth when it was only starting to become a planet 4.54 billion years ago?

$\endgroup$
5
  • 2
    $\begingroup$ this question is more appropriate for the Earth Science Stack Exchange $\endgroup$
    – DavePhD
    Commented Oct 17, 2014 at 16:16
  • 2
    $\begingroup$ This question is on-topic here and can stay, but it might very well find a better set of answers on Earth Science and I'll migrate if @LIUFA asks. $\endgroup$ Commented Oct 17, 2014 at 16:44
  • 1
    $\begingroup$ @dmckee Question already has answers, I believe it is best if it stays here. Thanks. $\endgroup$ Commented Oct 17, 2014 at 18:19
  • 1
    $\begingroup$ Quite good answers, too. $\endgroup$ Commented Oct 17, 2014 at 18:39
  • $\begingroup$ Am I the only person who's wondering if these two answers commute at all? I mean, they look good independently, but how do we tie them together to make a consistent picture? $\endgroup$
    – 299792458
    Commented Oct 17, 2014 at 19:02

2 Answers 2

17
$\begingroup$

The key to answering this question is the Goldschmidt classification of elements. Thirteen of the long-lived elements are siderophilic; they preferentially bind to iron. Those thirteen elements are significantly depleted in the Earth's crust compared to their prevalence on meteors, asteroids, and the Sun.

This list of thirteen does includes rhenium to gold, but it stops at gold. Eighteen of the long-lived elements are chalcophiles; they readily bind with a chalcogen other than oxygen (e.g., sulfur). Copper and silver, along with mercury to polonium fall in this category. These chalcophilic elements have a reduced tendency to migrate toward the center of the Earth because of their greater affinity for combining with lighter elements.

That list of thirteen siderophilic elements also does not include the lanthanides or actinides. These elements, along with a number of lighter elements, are lithophiles. The lithophiles have a very marked tendency to combine with oxygen, and with other lithophiles. These lithophilic elements have an even more strongly reduced tendency to migrate toward the center of the Earth than do the chalcophiles.

$\endgroup$
8
$\begingroup$

Actually, they are still currently sinking to the core. Earth's internal heat comes from a number of sources, and one of these is the release of gravitational energy from the heavy elements migrating further toward the center. A similar statement holds for other planets. This isn't the majority of the source of heat. Other sources are the original thermal inventory, and also radioactive decay. The intensified stratification of heavy elements toward the core and lighter elements toward the surface comprises a non-negligible source of heat, but still much smaller than those other sources.

However, this movement is generally happening in the mobile parts of Earth's center. Our planet's mantle has circulation currents, and I think we should call this a requirement for the separation process to happen. Of course the elements are significantly mixed together. It's only over very long time frames that the process happens.

Consider a lattice of atoms. With just about any material selection you make, the chemical bonds strength will vastly dwarf the buoyancy difference between different atoms of molecules. So we might wonder why the materials ever stratify, but this is because things get shaken up. Consider a pile of sand, where some grains are heavier. An undisturbed pile should have no tendency to stratify. However, if you shake it up for a long time, the heavy particles will move toward the bottom. The thermal flux from Earth's internal heat is the force that "shakes up" its elements.

Interestingly, the Earth's core and crust have their own unique reasons for being relatively stable... although not completely stable. The core has little thermal driving force behind it, because most of the heat production term comes from layers at larger radii. This promotes a very static state in the center. The crust is cooled to temperatures much lower than the interior, and generally rock is stable and solid here. Now both of these should come with a good deal of qualifiers. Obviously volcanoes shake up the crust, and the fact that I'm tying this exemplifies the fact that things do move on Earth's surface occasionally.

But exactly how stratified is Earth now? The density and gravity field strength follow directly from each other. It's not hard to get some data on this.

density with radius

Here, you can see the density plotted over the Earth's radii. It is sloping very heavily, and the core is very dense, like Lead, but heavier. I find that impressive, but it could still get further stratified.

So let me present an alternative question: since the density of Uranium is around 19 g/cm3, why don't we get a pocket of pure Uranium at the center? Well there's just no mechanism to do that because nothing is shaking up the crust, and the driving force putters out to nothing toward the center.

$\endgroup$
3
  • $\begingroup$ The density of the core is mainly a matter of pressure, not one of elemental composition. I would also think that the actual equilibrium distribution has to take the solution phase diagrams into account. Do we know those for heavy elements in nickel and iron? $\endgroup$
    – CuriousOne
    Commented Oct 17, 2014 at 17:17
  • $\begingroup$ @CuriousOne That's true, and I was walking a thin line with the comparison. The values for density should be considered "vacuum" values, constituting a minimum. While pressure increases density, the core under pressure is still less dense than Uranium metal in free space. The fact that densities combine in a non-linear fashion also obviously blows up the complexity, but I have no particular insight to share on that matter. $\endgroup$ Commented Oct 17, 2014 at 18:37
  • 1
    $\begingroup$ As related in @DaveHammen 's answer, there are the affinities of the elements to consider, ie, what compounds and solid solutions do they form. After some of that is sorted out, then the relative densities and environmental stabilities of those compounds and solid solutions can be considered within the paradigm of your answer. $\endgroup$
    – Eubie Drew
    Commented Oct 22, 2015 at 5:12

Not the answer you're looking for? Browse other questions tagged or ask your own question.