In deriving the maximum kinetic energy of photoelectrons in the photoelectric effect, Young & Freedman says that "As an electron moves from the cathode to the anode, the potential decreases by $V_0$ and negative work $-eV_0$ is done on the (negatively charged) electron."
For context, $V_0$ refers to the stopping potential, and the potential of the anode relative to the cathode is negative, and electrons are repelled from the anode.
I'm confused because as the electrons move from the cathode to the anode i.e. from (+) to (-), shouldn't its potential increase by $V_0$, not decrease? Also, why is there negative work being done on the electron?