I was reading the book Introduction to Quantum Mechanics by Daniel Griffith, and also following Brant Carlson's videos. He basically makes videos about parts of the book. The book was discussing $\frac{\mathrm d\langle x\rangle}{\mathrm dt}$, and this spiraled into getting the expectation value of momentum. We are then introduced to the operator used for momentum:
$$\langle p\rangle =\int \psi^*\left(-~\mathrm i\hbar\left(\frac{\partial}{\partial x}\right)\right)\psi~\mathrm dx$$ But in the Brant Carlson video on the topic, he states:
$$\langle \hat p\rangle =\int \psi^*\left(-~\mathrm i\hbar\left(\frac{\partial}{\partial x}\right)\right)\psi ~\mathrm dx$$
My question is whether this means that $\langle p\rangle =\langle \hat p\rangle\,.$ If this statement is true then the expectation value of $p$ is the same as the expectation value of the momentum operator.
This is the link to the video.