How do we determine the gradient and curl of a scalar/vector field in polar coordinates? For instance, if we have the following potential energy function for a force,
$$U = \frac{kx}{(x^2+y^2)^{3/2}}$$
it makes much more sense to compute the force in polar coordinates
$$U=\frac{k\cos\theta}{r^2}$$
But what is $\vec{\nabla}\cdot U$ in this case? The first thing that comes to mind is
$$\vec{F} = \frac{\partial U}{\partial r}\hat{r}+\frac{\partial U}{\partial\theta}\hat{\theta}$$
But that can't true, since the dimensions don't work out. Similarly, how do we calculate the curl for a vector field in polar coordinates? For instance, a central force like
$$F = -\frac{A}{r^2}\hat{r}$$
is much easier to deal with in polar.
I am a beginner in calculus, vector calculus in particular is a completely alien field to me. I would appreciate it if the answer could be kept as simple as possible.
Moreover, apart from the mathematical definition, it would be nice if the answer could include some reasoning (physical as well as mathematical) on why the curl and gradient are what they are in polar coordinates and how they tie to their counterparts in Cartesian coordinates.