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Recently I have been reading about the fourth state of matter, viz.Plasma. Everywhere I read that plasma is formed when Gases are given enough energy and they lose their electrons to form a "cloud" of free electrons and cations i.e. when gases are ionised.

In a plasma ball, the gas inside the ball is a noble gas. Even though noble gases are chemically inert and won't lose electrons much easily, as compared to other gases I am unable to understand why are they used ?

(Please correct me if I am wrong somewhere.Thank You.)

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  • $\begingroup$ Are you talking about a plasma globe? $\endgroup$
    – Brionius
    Commented Jan 15, 2015 at 14:30
  • $\begingroup$ Yeah.I think they are the same things.Although I didn't quite understand this wikipedia article. $\endgroup$
    – Abdullah
    Commented Jan 15, 2015 at 14:31

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Noble gases do not form molecular bonds as easily as other elements, true, because it's usually energetically unfavorable - a molecule containing a noble gas often would have more energy than the reactants.

However, it's not difficult at all to ionize noble gases with a static electric field, or EM radiation, or heating, or other means. That is to say, it is harder to ionize noble gases than other elements with similar electron cloud sizes but incomplete shells, but the difference is so small that it makes no difference in most applications.

In fact, noble gases are desirable for applications like plasma globes because they are non-reactive. If you have a gas inside something that's not supposed to open up, you don't want the gas corroding electrodes, or degrading surfaces, or any other effects caused by more reactive chemicals.

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  • $\begingroup$ Thank you! I think I got it, but, "....difference is so small". I could not get it. $\endgroup$
    – Abdullah
    Commented Jan 15, 2015 at 14:48
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    $\begingroup$ @Abdullah - Brionius meant that the input energy difference between liberating a noble gas electron and an electron from another atom with similar electron orbits is small enough not to matter. $\endgroup$ Commented Jan 18, 2015 at 14:04

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