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Cosmas Zachos
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Does Goldstone boson absorbtion-boson absorption by $W$ and $Z$ bosons mean that their masses are stochastic?

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Qmechanic
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Does Goldstone boson absorbtion by W$W$ and Z$Z$ bosons mean their masses are stochastic?

I have heard it explained that a complex doublet scalar field produces the Higgs boson, and also three Goldstone bosons which are absorbed by W $W$ and Z$Z$ bosons, giving them mass.

Does this mean that the W $W$ and Z$Z$ absorb (and presumably emit) Goldstone bosons as they move through this scalar field?

My main question is: does this mean that their mass is the fluctuating result of an approximate energy equilibrium reached in a stochastic process?

A couple of tangential questions:

  • Does this mean that empty space is full of Goldstone bosons which are doing nothing in the absence of any W or Z bosons?

  • Does this mean that two very close W and Z bosons will have to share Goldstone bosons and hence lower mass?

Does Goldstone boson absorbtion by W and Z bosons mean their masses are stochastic?

I have heard it explained that a complex doublet scalar field produces the Higgs boson, and also three Goldstone bosons which are absorbed by W and Z bosons, giving them mass.

Does this mean that the W and Z absorb (and presumably emit) Goldstone bosons as they move through this scalar field?

My main question is: does this mean that their mass is the fluctuating result of an approximate energy equilibrium reached in a stochastic process?

A couple of tangential questions:

  • Does this mean that empty space is full of Goldstone bosons which are doing nothing in the absence of any W or Z bosons?

  • Does this mean that two very close W and Z bosons will have to share Goldstone bosons and hence lower mass?

Does Goldstone boson absorbtion by $W$ and $Z$ bosons mean their masses are stochastic?

I have heard it explained that a complex doublet scalar field produces the Higgs boson, and also three Goldstone bosons which are absorbed by $W$ and $Z$ bosons, giving them mass.

Does this mean that the $W$ and $Z$ absorb (and presumably emit) Goldstone bosons as they move through this scalar field?

My main question is: does this mean that their mass is the fluctuating result of an approximate energy equilibrium reached in a stochastic process?

A couple of tangential questions:

  • Does this mean that empty space is full of Goldstone bosons which are doing nothing in the absence of any W or Z bosons?

  • Does this mean that two very close W and Z bosons will have to share Goldstone bosons and hence lower mass?

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spraff
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Does Goldstone boson absorbtion by W and Z bosons mean their masses are stochastic?

I have heard it explained that a complex doublet scalar field produces the Higgs boson, and also three Goldstone bosons which are absorbed by W and Z bosons, giving them mass.

Does this mean that the W and Z absorb (and presumably emit) Goldstone bosons as they move through this scalar field?

My main question is: does this mean that their mass is the fluctuating result of an approximate energy equilibrium reached in a stochastic process?

A couple of tangential questions:

  • Does this mean that empty space is full of Goldstone bosons which are doing nothing in the absence of any W or Z bosons?

  • Does this mean that two very close W and Z bosons will have to share Goldstone bosons and hence lower mass?