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0 votes
0 answers
96 views

Algebraic independence and substitution for quadratics

Let $f_{1},...,f_{n-1} \in \mathbb{F}[x_1,...,x_n]$ such that $\{ f_1,..., f_{n-1},x_n \}$ is algebraically independent over $\mathbb{F}$. Let $G \in \mathbb{F}[x_1,...,x_n,y_1,...,y_{n-1}]\...
Rishabh Kothary's user avatar
0 votes
0 answers
112 views

Relation between minimality and algebraic independence for binomials?

$\DeclareMathOperator\supp{supp}$Given $f_1,...,f_n \in \mathbb{F}[x_1,...,x_n]$ such that $f_1 = x_1 + q_1$ $f_2 = x_2 + q_2$ $\cdot \cdot \cdot$ $f_{n-1} = x_{n-1} + q_{n-1}$ $f_{n} = q_n$ such that ...
Rishabh Kothary's user avatar
2 votes
1 answer
200 views

Minimality implies algebraic independence?

$\DeclareMathOperator\supp{supp}$Given $f_1,...,f_n \in \mathbb{F}[x_1,...,x_n]$ such that $f_1 = x_1 + q_1$ $f_2 = x_2 + q_2$ $\cdot \cdot \cdot$ $f_{n-1} = x_{n-1} + q_{n-1}$ $f_{n} = q_n$ such that ...
Rishabh Kothary's user avatar
4 votes
1 answer
330 views

GCD in $\mathbb{F}_3[T]$ with powers of linear polynomials

This is a continuation of my previous question on $\gcd$s of polynomials of type $f^n - f$. Let us call $n > 1$ simple at a prime $p$ when $p-1 \mid n-1$ but $p^k - 1 \not\mid n-1$ for all $k > ...
Martin Brandenburg's user avatar
0 votes
0 answers
89 views

Representing an $m$ dimensional quadratic polynomial as a polynomial on $\mathbb F_{q^m}$

We can represent $\mathbb{F}_{q^m}$ as $\mathbb{F}_q[\alpha]$ where $\alpha$ is root of an irreducible $m$-degree polynomial on $\mathbb{F}_q$. By sending $\sum_{i=0}^{m-1} c_i\alpha^i \mapsto (c_{m-1}...
user's user avatar
  • 1
2 votes
0 answers
116 views

When $\gcd(P(x),Q(x))\bmod R(x)=\gcd(P(x) \bmod R(x),Q(x) \bmod R(x))$?

Let's $P,Q\in\mathbb K[x]$, with $\mathbb K$ a finite field. On what necessary and sufficient condition on $R \in \mathbb K[x]$ is it : $\gcd(P(x),Q(x))\bmod R(x)=\gcd(P(x) \bmod R(x),Q(x) \bmod R(x))...
Dattier's user avatar
  • 3,824
10 votes
1 answer
320 views

Proving that polynomials belonging to a certain family are reducible

In an article, I've found the following result. Unfortunately, it was derived from a general, somewhat complicated theory, that would be cumbersome for this result alone. Assume that $\mathbb F_p$ is ...
MikeTeX's user avatar
  • 687
7 votes
1 answer
979 views

Polynomials which are functionally equivalent over finite fields

Recall that two polynomials over a finite field are not necessarily considered equal, even if they evaluate to the same value at every point. For example, suppose $f(x) = x^2 + x + 1$ and $g(x) = 1$. ...
Gautam's user avatar
  • 1,703
21 votes
1 answer
577 views

Existence of a polynomial $Q$ of degree $\geq (p-1)/4$ in $\mathbb F_p[x]$ such that $QQ'$ factorizes into distinct linear factors

For all primes up to $p=89$ there exists a product $Q=\prod_{j=1}^d(x-a_j)$ involving $d\geq (p-1)/4$ distinct linear factors $x-a_j$ in $\mathbb F_p[x]$ such that $Q'$ has all its roots in $\mathbb ...
Roland Bacher's user avatar
11 votes
4 answers
1k views

Explicit large finite fields in characteristic $2$

Every finite field of characteristic $2$ ist given by $\mathbb{F}_2[x]/P(x)$ for some irreducible polynomial $P\in \mathbb{F}_2[x]$. For small degree, a simple algorithm gives a way to find $P$. Is ...
Jérémy Blanc's user avatar
4 votes
1 answer
647 views

Jacobian criterion for algebraic independence over a perfect field in positive characteristics

It is well known that the Jacobian criterion for algebraic independence does not hold in general for fields of positive characteristics. However, the following partial statement seems promising: ...
Xing Gu's user avatar
  • 935
2 votes
0 answers
66 views

Partitioning a given set into root set of two polynomials or non zero set of two polynomials simultaneously

Let $p,q$ be two prime numbers and let $p<q.$ Also let, $\mathbb{Z}_p$ and $\mathbb{Z}_q$ denote the fields formed by integers modulo $p$ and modulo $q$ respectively (with respect to the modulo $p$ ...
Aditya Guha Roy's user avatar
11 votes
1 answer
472 views

Greatest common divisor in $\mathbb{F}_p[T]$ with powers of linear polynomials

Let $n>1$ and $p$ be an odd prime with $p-1 \mid n-1$ such that $p^k - 1 \mid n-1$ does not hold for any $k>1$. Notice that, since $p-1 \mid n-1$, we have $T^p - T \mid T^n-T$ in $\mathbb{F}_p[T]...
Martin Brandenburg's user avatar
6 votes
0 answers
114 views

A question about the span of a sequence of polynomials satisfying a linear recurrence

Let F be a finite field and A(n) in F[t], n in N, be defined by a linear recurrence with coefficients in F[t], together with initial conditions. Is there a decision procedure for determining whether ...
paul Monsky's user avatar
  • 5,412
4 votes
0 answers
253 views

When is a given polynomial a square of another polynomial?

I meet a problem in which I hope to show a special polynomial is not a square of another polynomial. More precisely, let's consider the polynomial $f(x):= 1-x+2bx^n-2bx^{n+1}-b^2x^{2n-1}+2b^2x^{2n}-b^...
Joy-Joy's user avatar
  • 271

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