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Questions tagged [inequalities]

Questions about handling with inequalities with, e.g., Reduce, Solve, FindInstance etc., their application in defining Regions, and ways to incorporate them into other computations, e.g. integration.

0 votes
0 answers
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How to determine the validity of inequalities under given premises? [closed]

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csn899's user avatar
  • 4,521
0 votes
0 answers
44 views

Why is there a difference in computational speed when judging the size of inequalities in these two forms? [closed]

Method One: Reduce[ForAll[{x, y, z}, {x > y > 1 > z > 0, a == (1 + x z)/z, b == (1 + x y)/x, c == (1 + y z)/y}, a > b && c < a]] ...
csn899's user avatar
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0 votes
1 answer
67 views

How to perform linear programming in Mathematica based on the following conditions?

How to perform linear programming in Mathematica based on the following conditions, to draw the feasible region defined by -1 <= a + b <= 1 and 1 <= a - b <= 3, and find the range of t==3 ...
csn899's user avatar
  • 4,521
2 votes
1 answer
230 views

Why does FindInstance[x>0,x] give 27? [closed]

Why does FindInstance[x>0,x] give 27? I would think it would give 1… maybe 2 or some small positive decimal.
Just Some Old Man's user avatar
0 votes
1 answer
59 views

Verifying set emptiness with FindInstance versus Reduce [closed]

I have a semialgebraic set in $\mathbb{R}^4$ that I believe to be empty. FindInstance claims that it is empty in less than ten seconds. But Reduce has run for a week without visible progress --- and ...
Lyle Ramshaw's user avatar
0 votes
1 answer
51 views

Inequality too complex for Mathematica to solve? [closed]

I'm trying to solve some quite complicated inequalities (not a system), one of them for example being ...
oanesdof's user avatar
1 vote
1 answer
110 views

Unable to solve/reduce geometric Brownian motion inequality

I am trying to solve a few inequalities like the one below for Z: S * Exp[(mu - sigma^2/2)*T + Sqrt[T]*sigma*Z] > k Manually,...
Phil-ZXX's user avatar
  • 471
3 votes
1 answer
110 views

How can I solve this inequation over positive integers?

$$2023^i + 2023^{101-i}(-1)^i < 0, \quad i\in \mathbb N^+$$ My code: Reduce[2023^x+2023^(101-x)*(-1)^x<0 && x ∈ PositiveIntegers, x] gives an error ...
neo742's user avatar
  • 45
1 vote
1 answer
89 views

Most efficient way of defining the following sets for every step $n$

For each $n\in\mathbb{N}$, how do we compute sets $A_n$ and $B_n$ below: Let $A_1=[0,2/3)$. Let $B_1=(2/3,1]$. If $A_n$ is a union of intervals, then for each interval cut out the middle $1/2^{n+1}$ ...
Arbuja's user avatar
  • 81
1 vote
1 answer
70 views

How can I solve this inequality? Can I provide extra information when doing Solve?

I am new to Mathematica so I could really use your help. I am hoping to figure out the condition that the following function is larger than 0. I tried to FullSimplify it and to simplify it myself ...
C. K's user avatar
  • 25
5 votes
2 answers
129 views

Simplifying a logical expression with multivariate polynomials

I have several expressions similar to a (a b + c d) != 0 || b (a b + c d) != 0 || c (a b + c d) != 0 || d (a b + c d) != 0 and I would like to reduce them ...
მამუკა ჯიბლაძე's user avatar
1 vote
1 answer
61 views

Get limits of values from inequalites

My code above as below; ...
Soon's user avatar
  • 648
0 votes
2 answers
145 views

How to numerically find complex non-real roots of a function?

Using Mathematica, how can we numerically find only complexes, but not real roots, of a function? For example, if we have f:C->C, and we have roots like, R1,R2,...,Rn (real roots, without imaginary ...
GarouDan's user avatar
  • 1,536
2 votes
1 answer
109 views

Equation different plots

I have this equation to plot. f[x]*g[x] >= 310 the problem is how should it be converted? should I write ...
lia's user avatar
  • 347
1 vote
0 answers
103 views

Solving simple inequality gets MMA into an infinite loop [closed]

I was solving inequalities and here is a very simplified version of what I am seeing. When you do the following, all is well. Reduce[3^n < 250, n, Integers] ...
Moo's user avatar
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