The known conditions are:
f[2 x + 1 _] = x^2 - 2 x
How to find the analytical formula f [x] of this function?
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1 Answer
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RSolve[{f[2 x + 1] == x^2 - 2 x}, f[x], x] // Simplify // Expand
RSolve[f[2 x + 1 ] == x^2 - 2 x, f[x], x]? $\endgroup$Simplify /@ (f[2 x + 1] == x^2 - 2 x /. Solve[y == 2 x + 1, x][[1]]) /. {y -> x, Equal -> Rule}$\endgroup$