Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Results tagged with limits
Search options not deleted
user 961461
Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.
3
votes
Accepted
Limit $\lim_{k\to\infty}\left(\sum_{r=1}^{k-1}\zeta\left(2r\right)\frac{\left(-1\right)^{r+k...
{k=N+1}^{\infty}{\frac{1}{k^2}}<\sum_{k=2}^N{\frac{\varepsilon}{2^{k-1}}}+\frac{\varepsilon}{2^N}=\varepsilon
\end{align*}
By utilizing that cauchy stuff (name forgotten) and the basic definition of limits …
3
votes
1
answer
31
views
Evaluation of a limit involving gamma function
Basically I try to answer this question. I am almost able to prove it straight on, but I hit a roadblock at the very last step. Namely, the limit
$$
\lim_{n\rightarrow \infty} \left( \sqrt[n+1]{\Gamma …
5
votes
Conjecture: $\,\lim\limits_{n\to\infty}\int_0^1 (1+|\sin{nx}|)^{-2}\mathrm dx=\frac{4}{3\pi}$
=\frac{4}{3\pi}
\end{align*}
(1) Since the integrand is bounded, Lebesgue Dominated Convergence theorem could be utilized here to drag the $d$ out.
(2) By Moore-Osgood theorem, we can interchange the limits …
14
votes
Accepted
What is the mean value of $|\sin x +\sin (\pi x)|$?
This is not a direct answer
$\require{AMScd}$
Funny enough, I cannot tackle the integral head on, but I do have a solution to the sum equivalent to that integral.
Let's consider following question:
Su …
4
votes
1
answer
75
views
A conjecture involving series with zeta function
\zeta \left( N-n \right)}=\sin\left(1\right)
$$
But I believe this can applied to a broader case of limits. …