Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with linear-algebra
Search options not deleted
user 243942
For questions on linear algebra, including vector spaces, linear transformations, systems of linear equations, spanning sets, bases, dimensions and vector subspaces.
3
votes
2
answers
326
views
How to show that $Im(f) = B$ iff $f$ is onto?
Let $f : A → B$
My teacher said that $\text{Im}(f)=\{f(b):b\in A\} = B$ iff $f$ is onto. I know that this statement is true because it is kind of obvious but is there a way to prove it?
- 2,013
0
votes
0
answers
253
views
Dual Space of $R^{n}$? [duplicate]
My teacher said (without explaining why) that because $R^{n}$ is finite dimensional then set of all linear functions (Dual space) is equal to the set of all continuous linear functions. Can someone ex …
- 2,013