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For basic questions about limits, continuity, derivatives, differentiation, integrals, and their applications, mainly of one-variable functions.

2 votes

Intuitive reasoning behind the Chain Rule in multiple variables?

Think of it in terms of causality & superposition. $$z = f(x,y)$$ If you keep $y$ fixed then $\frac{dz}{dt} = \frac{df}{dx} * \frac{dx}{dt}$ If you keep $x$ fixed then $\frac{dz}{dt} = \frac{df}{fy …
Jason S's user avatar
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1 vote

What does it mean to be going 40 mph (or 64 kph, etc.) at a given moment?

A state-variable kind of approach: (represents the physical states of a system) Newton's first law of motion says that without external forces, masses will move at constant velocity. Every change in …
Jason S's user avatar
  • 3,139
3 votes
Accepted

Using differential equations to graph velocity over time of a falling object subject to wind...

$$\begin{align*} \sum F &= ma\\ \frac{dv}{dt} &= a\\ &= \frac{\sum F}{m}\\ \sum F &= mg - kv\\ \frac{dv}{dt} &= g - \frac{k}{m} v\end{align*}$$ This is a differential equation with a solution of $$\ …
Jason S's user avatar
  • 3,139
1 vote

Maclaurin Series of $1/(1-x)$ derived from maclaurin series of $(1+x)^n$

Try division? $\dfrac {1}{1-x} = 1 + x + x^2 + x^3 ...$ (edit: I'm not sure why you would try to derive it from the series for $(1+x)^n$ )
Jason S's user avatar
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0 votes

Integration of $\frac{1}{u^4 + (4\zeta^2-2)u^2 + 1}$

Partial fraction expansion gives $$ \frac{1}{u^{4} + \left(4 \zeta^{2} - 2\right)u^{2} + 1} = \frac{1}{4\zeta\sqrt{\zeta^2-1}}\left(\frac{1}{u^2+a_1{}^2} - \frac{1}{u^2+a_2{}^2}\right) $$ and since $ …
Jason S's user avatar
  • 3,139
1 vote
3 answers
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Integration of $\frac{1}{u^4 + (4\zeta^2-2)u^2 + 1}$

I am trying to compute $$I(\zeta) = \int_{-\infty}^{\infty} \frac{1}{u^{4} + \left(4 \zeta^{2} - 2\right)u^{2} + 1}\, du$$ for positive real $\zeta$. Can anyone help? I'm way out of practice for inte …
Jason S's user avatar
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3 votes

Useful examples of pathological functions

$\displaystyle\frac{\sin(x)}{x}$ is useful; it has a singularity at $x=0$, but if you take the union of $\displaystyle y=\frac{\sin(x)}{x}$ with the point $(x=0,y=1)$ then you get $\text{sinc}(x/\pi)$ …