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0 votes
0 answers
41 views

Change order of summation

I need to change the summation order in the sum: $$ \sum\limits_{n=0}^{\infty} \sum\limits_{k=0}^{ n m } F(k, n - mk) $$ In Srivastava's book, I came across a similar formula \begin{array}{c} \sum\...
Leox's user avatar
  • 8,194
-2 votes
2 answers
105 views

Reference for ${}_nC^0 + {}_nC^1 + {}_nC^2 + \cdots + {}_nC^n = 2^n$ [closed]

How can I find, or what is a good reference for: $${}_nC^0 + {}_nC^1 + {}_nC^2 + \cdots + {}_nC^n = 2^n$$ I could write References [1] Binomial sums, Binomial Sums -- from Wolfram MathWorld but I need ...
Mocean's user avatar
  • 15
0 votes
1 answer
61 views

What is $\sum_{m=0}^{\lfloor k/3\rfloor}{2k\choose k-3m}$ [closed]

With the floor function, I am not sure how to approach this. Edit: I have a formula $\frac{1}{6}\left(4^k+2+3\frac{(2k)!}{(k!)^2} \right)$, but I got it purely from guess work.
nnabahi's user avatar
  • 101
-1 votes
0 answers
54 views

Closed form solution for $\displaystyle \sum _{i=r+1}^{k}\frac{1}{i-1} \cdot \frac{( n-i) !}{( k-i) !}$, where $n,k,r$ are constants and $r \leq k<n$ [closed]

Context I arrived at this summation, while computing a probability of The Secretary Problem. Question: Find Closed form for this or if possible simplify $$ \frac{r}{n}\sum_{i = r + 1}^{k}\frac{1}{i - ...
Adi's user avatar
  • 17
2 votes
2 answers
45 views

Given a set of integers, and the number of summations find the resulting frequencies

Given a set $X = \{x_1,x_2,...x_m\}\subset \mathbb{Z}$ and the number of allowed addends $N$. How can I find the frequency of every possible sum? Example: $X = \{-1, 2\}$ and $N=3$ then every ...
haifisch123's user avatar
-3 votes
0 answers
76 views

How can I show that summing $\sum_{i=1}^n\binom{i+1}2$ equals $\binom{n+2}3 $ [closed]

How can I show that $$\sum_{i=1}^n\binom{i+1}2=\binom{n+2}3 ?$$
Noodle's user avatar
  • 298
0 votes
0 answers
43 views

Closed form for nested sum involving ratios of binomial coefficients

I ran into the following nested sum of binomial coefficients in my research, but I couldn't find the closed form expression for it. I looked at various sources and still couldn't find the answer. So I ...
Weishun Zhong's user avatar
2 votes
0 answers
95 views

Fractional part of a sum

Define for $n\in\mathbb{N}$ $$S_n=\sum_{r=0}^{n}\binom{n}{r}^2\left(\sum_{k=1}^{n+r}\frac{1}{k^5}\right)$$ I need to find $\{S_n\}$ for $n$ large where $\{x\}$ denotes the fractional part of $x$. $$...
Max's user avatar
  • 840
0 votes
0 answers
29 views

The sum of the signed stirling numbers times the factorials

The sum of interest is the following... $$ \sum^{n}_{k=1} (k-1)!s(n,k) $$ Where the $s(n,k)$ are the signed Stirling number of the first kind. The sum is very close to other identities involving the ...
Aidan R.S.'s user avatar
5 votes
0 answers
58 views

Vanishing of Stirling number of second kind $S(n,k)$ for $k>n$ [duplicate]

Apologies for this question, but I feel I am missing some sort of trivial observation somehow. Stirling numbers of the second kind are given by the series: $$S(n,k)=\frac{1}{k!} \sum_{i=0}^{k} (-1)^i {...
mathieu_matheux's user avatar
3 votes
1 answer
78 views

Combinatorial Proof of the $\sum_{k=1}^{n} k^2 \binom{n}{k} = n(n + 1) 2^{n - 2}$ [duplicate]

How to prove that $$\sum_{k = 1}^{n}k^2\binom{n}{k} = n(n + 1)2^{n -2}$$ in an combinatorial way? I have a algebraic proof method, but I don't know how to use a combinatorial proof method to do it.
crimsnow's user avatar
3 votes
2 answers
110 views

high school math: summands

Let's say we have a question that asks you to find the amount of all possible integers adding up to a random number, lets just say 1287. However, the possible integers is restricted to explicitly 1's ...
jackhammer's user avatar
1 vote
1 answer
105 views

Spivak Exercise, Prove Vandermonde's Identity $\sum_{k=0}^{l}\binom{n}{k}\binom{m}{l-k}=\binom{n+m}{l}$

Prove that $$\sum_{k=0}^{l}\binom{n}{k}\binom{m}{l-k}=\binom{n+m}{l}$$ Hint: Apply the binomial theorem to $(1+x)^n(1+x)^m$ Proof: Following Spivak's advice, we have $\sum_{k=0}^{n}\binom{n}{k}x^k=(...
Edward Falls's user avatar
0 votes
0 answers
44 views

Choosing an ordered triplet of non-negative integers $(m_1, m_2, m_3)$ such that $m_1 + m_2 + m_3 = n$.

Define $$A = \{ (m_1, m_2, m_3) : m_1 \geq 0, m_2 \geq 0, m_3 \geq 0, m_1 + m_2 + m_3 = n\}$$ Given that $n \geq 0$ and $n, m_1, m_2, m_3 \in \mathbb{Z}^+$, then why it is the case that $$\vert A \...
microhaus's user avatar
  • 934
0 votes
2 answers
44 views

Trying to prove equivalence of combinatorial formula and nested summations

I’m sorry if this is a dumb problem, but I’m trying to get into mathematics and prove this but I’m only in 9th grade and haven’t found any sources on this: Prove that $$ {n \choose r} = \overbrace{ \...
Joproblox Bardouha's user avatar

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